\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t87\_scmyciel (TMMDe5SA6eHgTynoQV4fwMB8NoH4ndnMCUL)}
\maketitle
Let $ v4\_scmyciel : {{\iota}{\unicdbdjdcd}{o}}$ be given.
Let $ k3\_tarski : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k12\_scmyciel : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k4\_tarski : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (v4\_scmyciel~X0){\unicdbdjdcd}({\unicdcdadad} X1 .  (X1 \in k3\_tarski~(k12\_scmyciel~\\
X0)){\unicdbdjded}(\preoh (\preoh X1 \in k3\_tarski~X0){\unicdcdcdhd}(({\unicdcdadad} X2 .  \preoh (X2 \in k3\_tarski~X0){\unicdcdcdhd}\\
(X1=k4\_tarski~X2~(k3\_tarski~X0))){\unicdcdcdhd}(X1{\unicdcdgdad}k3\_tarski~X0))))\end{array}
\label{hyp:ehidfdpfdhdgngjhdgjgfgmg}
\end{equation}
\begin{theorem}\label{thm:ehidhdpfdhdgngjhdgjgfgmg}
$$\begin{array}{c}{\unicdcdadad} X0 .  (v4\_scmyciel~X0){\unicdbdjdcd}(k3\_tarski~X0 \in k3\_tarski~(k12\_scmyciel~\\
X0))\end{array}$$
\end{theorem}
\end{document}
