\documentclass{article}
\newtheorem{axiom}{Axiom}
\newtheorem{theorem}{Theorem}
\newtheorem{lemma}{Lemma}
\newtheorem{proposition}{Proposition}
\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
\newcommand\unicdcdcdbg{\cup}
\newcommand\unicdcdbdgd{\setminus}
\newcommand\unicdcdcdjd{\cap}
\newcommand\unicdcdadad{\forall}
\newcommand\unicdbdjdcd{\Rightarrow}
\newcommand\unicdcdadjd{\notin}
\newcommand\unicdbdjded{\Leftrightarrow}
\newcommand\unicdcdcdid{\lor}
\newcommand\unicdcdcdhd{\land}
\newcommand\uniddcgcg{\lambda}
\newcommand\unicdcdaddd{\exists}
\newcommand\unicdcdidid{\not\subseteq}
\newcommand\preoh[1]{\lnot #1}
\newcommand\mname[1]{{\mathsf{#1}}}
\begin{document}
\title{t8\_gfacirc1 (TMaGV9cwX9s92tDYWoLncGPjbSeCKUcbBzr)}
\maketitle
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k6\_margrel1 : {\iota}$ be given.
Let $ k1\_funct\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k4\_gfacirc1 : {\iota}$ be given.
Let $ k10\_finseq\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k15\_twoscomp : {\iota}$ be given.
Let $ k2\_binarith : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k9\_margrel1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ k8\_twoscomp : {\iota}$ be given.
Let $ k4\_twoscomp : {\iota}$ be given.
Let $ k2\_twoscomp : {\iota}$ be given.
Let $ k6\_numbers : {\iota}$ be given.
Let $ np\_\_1 : {\iota}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~k6\_margrel1){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~\\
X1~k6\_margrel1){\unicdbdjdcd}((k1\_funct\_1~k4\_gfacirc1~(k10\_finseq\_1~X0~X1)=\\
k2\_binarith~X0~(k9\_margrel1~X1)){\unicdcdcdhd}((k1\_funct\_1~k4\_gfacirc1~(k10\_finseq\_1~\\
X0~X1)=k1\_funct\_1~k15\_twoscomp~(k10\_finseq\_1~X0~X1)){\unicdcdcdhd}((k1\_funct\_1~\\
k4\_gfacirc1~(k10\_finseq\_1~X0~X1)=k1\_funct\_1~k8\_twoscomp~(k10\_finseq\_1~\\
(k1\_funct\_1~k4\_twoscomp~(k10\_finseq\_1~X0~X1))~(k1\_funct\_1~k2\_twoscomp~\\
(k10\_finseq\_1~X0~X1)))){\unicdcdcdhd}((k1\_funct\_1~k4\_gfacirc1~(k10\_finseq\_1~\\
k6\_numbers~k6\_numbers)=np\_\_1){\unicdcdcdhd}((k1\_funct\_1~k4\_gfacirc1~(k10\_finseq\_1~\\
k6\_numbers~np\_\_1)=k6\_numbers){\unicdcdcdhd}((k1\_funct\_1~k4\_gfacirc1~(k10\_finseq\_1~\\
np\_\_1~k6\_numbers)=k6\_numbers){\unicdcdcdhd}(k1\_funct\_1~k4\_gfacirc1~(k10\_finseq\_1~\\
np\_\_1~np\_\_1)=np\_\_1))))))))\end{array}
\label{hyp:ehedpfhgggbgdgjgchdgbd}
\end{equation}
\begin{theorem}\label{thm:ehidpfhgggbgdgjgchdgbd}
$$\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~k6\_margrel1){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~\\
X1~k6\_margrel1){\unicdbdjdcd}({\unicdcdadad} X2 .  (m1\_subset\_1~X2~k6\_margrel1){\unicdbdjdcd}(k1\_funct\_1~\\
k4\_gfacirc1~(k10\_finseq\_1~(k1\_funct\_1~k15\_twoscomp~(k10\_finseq\_1~\\
X0~X1))~X2)=k1\_funct\_1~k4\_gfacirc1~(k10\_finseq\_1~(k1\_funct\_1~\\
k4\_gfacirc1~(k10\_finseq\_1~X0~X1))~X2))))\end{array}$$
\end{theorem}
\end{document}
