\documentclass{article}
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\newtheorem{definition}{Definition}
\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
\newcommand\unicdcdgdad{\not=}
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\newcommand\preoh[1]{\lnot #1}
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\begin{document}
\title{t90\_arytm\_3 (TMckQUwiN7yTVy5r4evhnTpwWE2JJcGvQ6t)}
\maketitle
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k5\_arytm\_3 : {\iota}$ be given.
Let $ r3\_arytm\_3 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k9\_arytm\_3 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k11\_arytm\_3 : {\iota}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~k5\_arytm\_3){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~\\
X1~k5\_arytm\_3){\unicdbdjdcd}({\unicdcdadad} X2 .  (m1\_subset\_1~X2~k5\_arytm\_3){\unicdbdjdcd}(\preoh (r3\_arytm\_3~\\
X0~X1){\unicdcdcdhd}((r3\_arytm\_3~X1~(k9\_arytm\_3~X0~X2)){\unicdcdcdhd}({\unicdcdadad} X3 .  (m1\_subset\_1~\\
X3~k5\_arytm\_3){\unicdbdjdcd}(\preoh (X1=k9\_arytm\_3~X0~X3){\unicdcdcdhd}(r3\_arytm\_3~X3~X2)))))))\end{array}
\label{hyp:ehidgdpfbgchjhehngpfdd}
\end{equation}
Assume the following.
\begin{equation}
{{\unicdcdadad} X0 .  {{({{{m1\_subset\_1}~{X0}}~{k5\_arytm\_3}})}{\unicdbdjdcd}{({{{r3\_arytm\_3}~{k11\_arytm\_3}}~{X0}})}}}\label{hyp:ehgdedpfbgchjhehngpfdd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~k5\_arytm\_3){\unicdbdjdcd}(k9\_arytm\_3~X0~k11\_arytm\_3=\\
X0)\end{array}
\label{hyp:ehfdadpfbgchjhehngpfdd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  ((m1\_subset\_1~X0~k5\_arytm\_3){\unicdcdcdhd}(m1\_subset\_1~\\
X1~k5\_arytm\_3)){\unicdbdjdcd}(m1\_subset\_1~(k9\_arytm\_3~X0~X1)~k5\_arytm\_3)\end{array}
\label{hyp:egehpflgjdpfbgchjhehngpfdd}
\end{equation}
Assume the following.
\begin{equation}
{{{m1\_subset\_1}~{k11\_arytm\_3}}~{k5\_arytm\_3}}\label{hyp:egehpflgbdbdpfbgchjhehngpfdd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  ((m1\_subset\_1~X0~k5\_arytm\_3){\unicdcdcdhd}(m1\_subset\_1~\\
X1~k5\_arytm\_3)){\unicdbdjdcd}((r3\_arytm\_3~X0~X1){\unicdcdcdid}(r3\_arytm\_3~X1~X0))\end{array}
\label{hyp:dgpgogogfgdgehfgegogfgdhdhpfchddpfbgchjhehngpfdd}
\end{equation}
\begin{theorem}\label{thm:ehjdadpfbgchjhehngpfdd}
$$\begin{array}{c}{\unicdcdadad} X0 .  (m1\_subset\_1~X0~k5\_arytm\_3){\unicdbdjdcd}({\unicdcdadad} X1 .  (m1\_subset\_1~\\
X1~k5\_arytm\_3){\unicdbdjdcd}({\unicdcdadad} X2 .  (m1\_subset\_1~X2~k5\_arytm\_3){\unicdbdjdcd}(\preoh (\preoh \\
r3\_arytm\_3~(k9\_arytm\_3~X1~X2)~X0){\unicdcdcdhd}((X2{\unicdcdgdad}k11\_arytm\_3){\unicdcdcdhd}({\unicdcdadad} X3 .  \\
(m1\_subset\_1~X3~k5\_arytm\_3){\unicdbdjdcd}({\unicdcdadad} X4 .  (m1\_subset\_1~X4~k5\_arytm\_3){\unicdbdjdcd}\\
(\preoh (X0=k9\_arytm\_3~X3~X4){\unicdcdcdhd}((r3\_arytm\_3~X3~X1){\unicdcdcdhd}((r3\_arytm\_3~X4~X2){\unicdcdcdhd}\\
(X4{\unicdcdgdad}X2))))))))))\end{array}$$
\end{theorem}
\end{document}
