\documentclass{article}
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\newtheorem{example}{Example}
\newtheorem{conjecture}{Conjecture}
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\begin{document}
\title{t9\_hilbert3 (TMSiTu9tg6QokYnRqZSTTsrM3i6q2cmdo5M)}
\maketitle
Let $ m1\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}$ be given.
Let $ k1\_zfmisc\_1 : {{\iota}{\unicdbdjdcd}{\iota}}$ be given.
Let $ r1\_funct\_2 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{o}}}}}}}$ be given.
Let $ k5\_numbers : {\iota}$ be given.
Let $ k2\_tarski : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k1\_xboole\_0 : {\iota}$ be given.
Let $ np\_\_1 : {\iota}$ be given.
Let $ k1\_partfun1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}}}}$ be given.
Let $ k6\_numbers : {\iota}$ be given.
Let $ k5\_funct\_3 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k3\_subset\_1 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}$ be given.
Let $ k5\_funct\_4 : {{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{{\iota}{\unicdbdjdcd}{\iota}}}}}}$ be given.
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  (m1\_subset\_1~X1~(k1\_zfmisc\_1~X0)){\unicdbdjdcd}(r1\_funct\_2~\\
X0~k5\_numbers~X0~(k2\_tarski~k1\_xboole\_0~np\_\_1)~(k1\_partfun1~X0~\\
(k2\_tarski~k1\_xboole\_0~np\_\_1)~(k2\_tarski~k6\_numbers~np\_\_1)~k5\_numbers~\\
(k5\_funct\_3~X1~X0)~(k5\_funct\_4~k5\_numbers~k6\_numbers~np\_\_1~np\_\_1~\\
k6\_numbers))~(k5\_funct\_3~(k3\_subset\_1~X0~X1)~X0))\end{array}
\label{hyp:ehidpfigjgmgcgfgchehdd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  (m1\_subset\_1~X1~(k1\_zfmisc\_1~X0)){\unicdbdjdcd}(k3\_subset\_1~\\
X0~(k3\_subset\_1~X0~X1)=X1)\end{array}
\label{hyp:jgogghpgmgfhehjgghfgogfgdhdhpflgddpfdhfhcgdhfgehpfbd}
\end{equation}
Assume the following.
\begin{equation}
\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  (m1\_subset\_1~X1~(k1\_zfmisc\_1~X0)){\unicdbdjdcd}(m1\_subset\_1~\\
(k3\_subset\_1~X0~X1)~(k1\_zfmisc\_1~X0))\end{array}
\label{hyp:egehpflgddpfdhfhcgdhfgehpfbd}
\end{equation}
\begin{theorem}\label{thm:ehjdpfigjgmgcgfgchehdd}
$$\begin{array}{c}{\unicdcdadad} X0 .  {\unicdcdadad} X1 .  (m1\_subset\_1~X1~(k1\_zfmisc\_1~X0)){\unicdbdjdcd}(r1\_funct\_2~\\
X0~k5\_numbers~X0~(k2\_tarski~k1\_xboole\_0~np\_\_1)~(k1\_partfun1~X0~\\
(k2\_tarski~k1\_xboole\_0~np\_\_1)~(k2\_tarski~k6\_numbers~np\_\_1)~k5\_numbers~\\
(k5\_funct\_3~(k3\_subset\_1~X0~X1)~X0)~(k5\_funct\_4~k5\_numbers~k6\_numbers~\\
np\_\_1~np\_\_1~k6\_numbers))~(k5\_funct\_3~X1~X0))\end{array}$$
\end{theorem}
\end{document}
