:: MOD_3 semantic presentation begin Lm1: for R being Ring for a being Scalar of R st - a = 0. R holds a = 0. R proof let R be Ring; ::_thesis: for a being Scalar of R st - a = 0. R holds a = 0. R let a be Scalar of R; ::_thesis: ( - a = 0. R implies a = 0. R ) assume - a = 0. R ; ::_thesis: a = 0. R then - (- a) = 0. R by RLVECT_1:12; hence a = 0. R by RLVECT_1:17; ::_thesis: verum end; theorem Th1: :: MOD_3:1 for R being non empty non degenerated right_complementable add-associative right_zeroed doubleLoopStr holds 0. R <> - (1. R) proof let R be non empty non degenerated right_complementable add-associative right_zeroed doubleLoopStr ; ::_thesis: 0. R <> - (1. R) assume 0. R = - (1. R) ; ::_thesis: contradiction then 0. R = - (- (1. R)) by RLVECT_1:12 .= 1. R by RLVECT_1:17 ; hence contradiction ; ::_thesis: verum end; theorem Th2: :: MOD_3:2 for R being Ring for V being LeftMod of R for L being Linear_Combination of V for C being finite Subset of V st Carrier L c= C holds ex F being FinSequence of the carrier of V st ( F is one-to-one & rng F = C & Sum L = Sum (L (#) F) ) proof let R be Ring; ::_thesis: for V being LeftMod of R for L being Linear_Combination of V for C being finite Subset of V st Carrier L c= C holds ex F being FinSequence of the carrier of V st ( F is one-to-one & rng F = C & Sum L = Sum (L (#) F) ) let V be LeftMod of R; ::_thesis: for L being Linear_Combination of V for C being finite Subset of V st Carrier L c= C holds ex F being FinSequence of the carrier of V st ( F is one-to-one & rng F = C & Sum L = Sum (L (#) F) ) let L be Linear_Combination of V; ::_thesis: for C being finite Subset of V st Carrier L c= C holds ex F being FinSequence of the carrier of V st ( F is one-to-one & rng F = C & Sum L = Sum (L (#) F) ) let C be finite Subset of V; ::_thesis: ( Carrier L c= C implies ex F being FinSequence of the carrier of V st ( F is one-to-one & rng F = C & Sum L = Sum (L (#) F) ) ) assume A1: Carrier L c= C ; ::_thesis: ex F being FinSequence of the carrier of V st ( F is one-to-one & rng F = C & Sum L = Sum (L (#) F) ) set D = C \ (Carrier L); consider G being FinSequence of the carrier of V such that A2: G is one-to-one and A3: rng G = Carrier L and A4: Sum L = Sum (L (#) G) by VECTSP_6:def_6; consider p being FinSequence such that A5: rng p = C \ (Carrier L) and A6: p is one-to-one by FINSEQ_4:58; reconsider p = p as FinSequence of the carrier of V by A5, FINSEQ_1:def_4; A7: rng G misses rng p proof assume rng G meets rng p ; ::_thesis: contradiction then ex x being set st ( x in Carrier L & x in C \ (Carrier L) ) by A3, A5, XBOOLE_0:3; hence contradiction by XBOOLE_0:def_5; ::_thesis: verum end; A8: len p = len (L (#) p) by VECTSP_6:def_5; now__::_thesis:_for_k_being_Element_of_NAT_st_k_in_dom_p_holds_ (L_(#)_p)_._k_=_(0._R)_*_(p_/._k) let k be Element of NAT ; ::_thesis: ( k in dom p implies (L (#) p) . k = (0. R) * (p /. k) ) assume A9: k in dom p ; ::_thesis: (L (#) p) . k = (0. R) * (p /. k) then p /. k = p . k by PARTFUN1:def_6; then p /. k in C \ (Carrier L) by A5, A9, FUNCT_1:def_3; then A10: not p /. k in Carrier L by XBOOLE_0:def_5; k in dom (L (#) p) by A8, A9, FINSEQ_3:29; then (L (#) p) . k = (L . (p /. k)) * (p /. k) by VECTSP_6:def_5; hence (L (#) p) . k = (0. R) * (p /. k) by A10; ::_thesis: verum end; then A11: Sum (L (#) p) = (0. R) * (Sum p) by A8, RLVECT_2:67 .= 0. V by VECTSP_1:14 ; set F = G ^ p; take G ^ p ; ::_thesis: ( G ^ p is one-to-one & rng (G ^ p) = C & Sum L = Sum (L (#) (G ^ p)) ) A12: Sum (L (#) (G ^ p)) = Sum ((L (#) G) ^ (L (#) p)) by VECTSP_6:13 .= (Sum (L (#) G)) + (0. V) by A11, RLVECT_1:41 .= Sum L by A4, RLVECT_1:def_4 ; rng (G ^ p) = (Carrier L) \/ (C \ (Carrier L)) by A3, A5, FINSEQ_1:31 .= C by A1, XBOOLE_1:45 ; hence ( G ^ p is one-to-one & rng (G ^ p) = C & Sum L = Sum (L (#) (G ^ p)) ) by A2, A6, A12, A7, FINSEQ_3:91; ::_thesis: verum end; theorem Th3: :: MOD_3:3 for R being Ring for V being LeftMod of R for L being Linear_Combination of V for a being Scalar of R holds Sum (a * L) = a * (Sum L) proof let R be Ring; ::_thesis: for V being LeftMod of R for L being Linear_Combination of V for a being Scalar of R holds Sum (a * L) = a * (Sum L) let V be LeftMod of R; ::_thesis: for L being Linear_Combination of V for a being Scalar of R holds Sum (a * L) = a * (Sum L) let L be Linear_Combination of V; ::_thesis: for a being Scalar of R holds Sum (a * L) = a * (Sum L) let a be Scalar of R; ::_thesis: Sum (a * L) = a * (Sum L) set l = a * L; Carrier (a * L) c= Carrier L by VECTSP_6:28; then consider F being FinSequence of the carrier of V such that A1: ( F is one-to-one & rng F = Carrier L ) and A2: Sum (a * L) = Sum ((a * L) (#) F) by Th2; set f = (a * L) (#) F; set g = L (#) F; A3: len ((a * L) (#) F) = len F by VECTSP_6:def_5 .= len (L (#) F) by VECTSP_6:def_5 ; len ((a * L) (#) F) = len F by VECTSP_6:def_5; then A4: dom F = Seg (len ((a * L) (#) F)) by FINSEQ_1:def_3; A5: now__::_thesis:_for_k_being_Element_of_NAT_ for_v_being_Vector_of_V_st_k_in_dom_((a_*_L)_(#)_F)_&_v_=_(L_(#)_F)_._k_holds_ ((a_*_L)_(#)_F)_._k_=_a_*_v let k be Element of NAT ; ::_thesis: for v being Vector of V st k in dom ((a * L) (#) F) & v = (L (#) F) . k holds ((a * L) (#) F) . k = a * v let v be Vector of V; ::_thesis: ( k in dom ((a * L) (#) F) & v = (L (#) F) . k implies ((a * L) (#) F) . k = a * v ) assume that A6: k in dom ((a * L) (#) F) and A7: v = (L (#) F) . k ; ::_thesis: ((a * L) (#) F) . k = a * v set v9 = F /. k; A8: k in Seg (len ((a * L) (#) F)) by A6, FINSEQ_1:def_3; then A9: F /. k = F . k by A4, PARTFUN1:def_6; hence ((a * L) (#) F) . k = ((a * L) . (F /. k)) * (F /. k) by A4, A8, VECTSP_6:8 .= (a * (L . (F /. k))) * (F /. k) by VECTSP_6:def_9 .= a * ((L . (F /. k)) * (F /. k)) by VECTSP_1:def_16 .= a * v by A4, A7, A8, A9, VECTSP_6:8 ; ::_thesis: verum end; Sum L = Sum (L (#) F) by A1, VECTSP_6:def_6; hence Sum (a * L) = a * (Sum L) by A2, A3, A5, RLVECT_2:66; ::_thesis: verum end; definition let R be Ring; let V be LeftMod of R; let A be Subset of V; func Lin A -> strict Subspace of V means :Def1: :: MOD_3:def 1 the carrier of it = { (Sum l) where l is Linear_Combination of A : verum } ; existence ex b1 being strict Subspace of V st the carrier of b1 = { (Sum l) where l is Linear_Combination of A : verum } proof set A1 = { (Sum l) where l is Linear_Combination of A : verum } ; { (Sum l) where l is Linear_Combination of A : verum } c= the carrier of V proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in { (Sum l) where l is Linear_Combination of A : verum } or x in the carrier of V ) assume x in { (Sum l) where l is Linear_Combination of A : verum } ; ::_thesis: x in the carrier of V then ex l being Linear_Combination of A st x = Sum l ; hence x in the carrier of V ; ::_thesis: verum end; then reconsider A1 = { (Sum l) where l is Linear_Combination of A : verum } as Subset of V ; reconsider l = ZeroLC V as Linear_Combination of A by VECTSP_6:5; A1: A1 is linearly-closed proof thus for v, u being Vector of V st v in A1 & u in A1 holds v + u in A1 :: according to VECTSP_4:def_1 ::_thesis: for b1 being Element of the carrier of R for b2 being Element of the carrier of V holds ( not b2 in A1 or b1 * b2 in A1 ) proof let v, u be Vector of V; ::_thesis: ( v in A1 & u in A1 implies v + u in A1 ) assume that A2: v in A1 and A3: u in A1 ; ::_thesis: v + u in A1 consider l1 being Linear_Combination of A such that A4: v = Sum l1 by A2; consider l2 being Linear_Combination of A such that A5: u = Sum l2 by A3; reconsider f = l1 + l2 as Linear_Combination of A by VECTSP_6:24; v + u = Sum f by A4, A5, VECTSP_6:44; hence v + u in A1 ; ::_thesis: verum end; let a be Scalar of R; ::_thesis: for b1 being Element of the carrier of V holds ( not b1 in A1 or a * b1 in A1 ) let v be Vector of V; ::_thesis: ( not v in A1 or a * v in A1 ) assume v in A1 ; ::_thesis: a * v in A1 then consider l being Linear_Combination of A such that A6: v = Sum l ; reconsider f = a * l as Linear_Combination of A by VECTSP_6:31; a * v = Sum f by A6, Th3; hence a * v in A1 ; ::_thesis: verum end; Sum l = 0. V by VECTSP_6:15; then 0. V in A1 ; hence ex b1 being strict Subspace of V st the carrier of b1 = { (Sum l) where l is Linear_Combination of A : verum } by A1, VECTSP_4:34; ::_thesis: verum end; uniqueness for b1, b2 being strict Subspace of V st the carrier of b1 = { (Sum l) where l is Linear_Combination of A : verum } & the carrier of b2 = { (Sum l) where l is Linear_Combination of A : verum } holds b1 = b2 by VECTSP_4:29; end; :: deftheorem Def1 defines Lin MOD_3:def_1_:_ for R being Ring for V being LeftMod of R for A being Subset of V for b4 being strict Subspace of V holds ( b4 = Lin A iff the carrier of b4 = { (Sum l) where l is Linear_Combination of A : verum } ); theorem Th4: :: MOD_3:4 for x being set for R being Ring for V being LeftMod of R for A being Subset of V holds ( x in Lin A iff ex l being Linear_Combination of A st x = Sum l ) proof let x be set ; ::_thesis: for R being Ring for V being LeftMod of R for A being Subset of V holds ( x in Lin A iff ex l being Linear_Combination of A st x = Sum l ) let R be Ring; ::_thesis: for V being LeftMod of R for A being Subset of V holds ( x in Lin A iff ex l being Linear_Combination of A st x = Sum l ) let V be LeftMod of R; ::_thesis: for A being Subset of V holds ( x in Lin A iff ex l being Linear_Combination of A st x = Sum l ) let A be Subset of V; ::_thesis: ( x in Lin A iff ex l being Linear_Combination of A st x = Sum l ) thus ( x in Lin A implies ex l being Linear_Combination of A st x = Sum l ) ::_thesis: ( ex l being Linear_Combination of A st x = Sum l implies x in Lin A ) proof assume x in Lin A ; ::_thesis: ex l being Linear_Combination of A st x = Sum l then x in the carrier of (Lin A) by STRUCT_0:def_5; then x in { (Sum l) where l is Linear_Combination of A : verum } by Def1; hence ex l being Linear_Combination of A st x = Sum l ; ::_thesis: verum end; given k being Linear_Combination of A such that A1: x = Sum k ; ::_thesis: x in Lin A x in { (Sum l) where l is Linear_Combination of A : verum } by A1; then x in the carrier of (Lin A) by Def1; hence x in Lin A by STRUCT_0:def_5; ::_thesis: verum end; theorem Th5: :: MOD_3:5 for x being set for R being Ring for V being LeftMod of R for A being Subset of V st x in A holds x in Lin A proof let x be set ; ::_thesis: for R being Ring for V being LeftMod of R for A being Subset of V st x in A holds x in Lin A let R be Ring; ::_thesis: for V being LeftMod of R for A being Subset of V st x in A holds x in Lin A let V be LeftMod of R; ::_thesis: for A being Subset of V st x in A holds x in Lin A let A be Subset of V; ::_thesis: ( x in A implies x in Lin A ) deffunc H1( Vector of V) -> Element of the carrier of R = 0. R; assume A1: x in A ; ::_thesis: x in Lin A then reconsider v = x as Vector of V ; consider f being Function of the carrier of V, the carrier of R such that A2: f . v = 1. R and A3: for u being Vector of V st u <> v holds f . u = H1(u) from FUNCT_2:sch_6(); reconsider f = f as Element of Funcs ( the carrier of V, the carrier of R) by FUNCT_2:8; ex T being finite Subset of V st for u being Vector of V st not u in T holds f . u = 0. R proof take T = {v}; ::_thesis: for u being Vector of V st not u in T holds f . u = 0. R let u be Vector of V; ::_thesis: ( not u in T implies f . u = 0. R ) assume not u in T ; ::_thesis: f . u = 0. R then u <> v by TARSKI:def_1; hence f . u = 0. R by A3; ::_thesis: verum end; then reconsider f = f as Linear_Combination of V by VECTSP_6:def_1; A4: Carrier f c= {v} proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in Carrier f or x in {v} ) assume x in Carrier f ; ::_thesis: x in {v} then consider u being Vector of V such that A5: x = u and A6: f . u <> 0. R ; u = v by A3, A6; hence x in {v} by A5, TARSKI:def_1; ::_thesis: verum end; then reconsider f = f as Linear_Combination of {v} by VECTSP_6:def_4; A7: Sum f = (1. R) * v by A2, VECTSP_6:17 .= v by VECTSP_1:def_17 ; {v} c= A by A1, ZFMISC_1:31; then Carrier f c= A by A4, XBOOLE_1:1; then reconsider f = f as Linear_Combination of A by VECTSP_6:def_4; Sum f = v by A7; hence x in Lin A by Th4; ::_thesis: verum end; theorem Th6: :: MOD_3:6 for R being Ring for V being LeftMod of R holds Lin ({} the carrier of V) = (0). V proof let R be Ring; ::_thesis: for V being LeftMod of R holds Lin ({} the carrier of V) = (0). V let V be LeftMod of R; ::_thesis: Lin ({} the carrier of V) = (0). V set A = Lin ({} the carrier of V); now__::_thesis:_for_v_being_Vector_of_V_holds_ (_(_v_in_Lin_({}_the_carrier_of_V)_implies_v_in_(0)._V_)_&_(_v_in_(0)._V_implies_v_in_Lin_({}_the_carrier_of_V)_)_) let v be Vector of V; ::_thesis: ( ( v in Lin ({} the carrier of V) implies v in (0). V ) & ( v in (0). V implies v in Lin ({} the carrier of V) ) ) thus ( v in Lin ({} the carrier of V) implies v in (0). V ) ::_thesis: ( v in (0). V implies v in Lin ({} the carrier of V) ) proof assume v in Lin ({} the carrier of V) ; ::_thesis: v in (0). V then A1: v in the carrier of (Lin ({} the carrier of V)) by STRUCT_0:def_5; the carrier of (Lin ({} the carrier of V)) = { (Sum l0) where l0 is Linear_Combination of {} the carrier of V : verum } by Def1; then ex l0 being Linear_Combination of {} the carrier of V st v = Sum l0 by A1; then v = 0. V by VECTSP_6:16; hence v in (0). V by VECTSP_4:35; ::_thesis: verum end; assume v in (0). V ; ::_thesis: v in Lin ({} the carrier of V) then v = 0. V by VECTSP_4:35; hence v in Lin ({} the carrier of V) by VECTSP_4:17; ::_thesis: verum end; hence Lin ({} the carrier of V) = (0). V by VECTSP_4:30; ::_thesis: verum end; theorem :: MOD_3:7 for R being Ring for V being LeftMod of R for A being Subset of V holds ( not Lin A = (0). V or A = {} or A = {(0. V)} ) proof let R be Ring; ::_thesis: for V being LeftMod of R for A being Subset of V holds ( not Lin A = (0). V or A = {} or A = {(0. V)} ) let V be LeftMod of R; ::_thesis: for A being Subset of V holds ( not Lin A = (0). V or A = {} or A = {(0. V)} ) let A be Subset of V; ::_thesis: ( not Lin A = (0). V or A = {} or A = {(0. V)} ) assume that A1: Lin A = (0). V and A2: A <> {} ; ::_thesis: A = {(0. V)} thus A c= {(0. V)} :: according to XBOOLE_0:def_10 ::_thesis: {(0. V)} c= A proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in A or x in {(0. V)} ) assume x in A ; ::_thesis: x in {(0. V)} then x in Lin A by Th5; then x = 0. V by A1, VECTSP_4:35; hence x in {(0. V)} by TARSKI:def_1; ::_thesis: verum end; set y = the Element of A; let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in {(0. V)} or x in A ) assume x in {(0. V)} ; ::_thesis: x in A then A3: x = 0. V by TARSKI:def_1; ( the Element of A in A & the Element of A in Lin A ) by A2, Th5; hence x in A by A1, A3, VECTSP_4:35; ::_thesis: verum end; theorem Th8: :: MOD_3:8 for R being Ring for V being LeftMod of R for A being Subset of V for W being strict Subspace of V st 0. R <> 1. R & A = the carrier of W holds Lin A = W proof let R be Ring; ::_thesis: for V being LeftMod of R for A being Subset of V for W being strict Subspace of V st 0. R <> 1. R & A = the carrier of W holds Lin A = W let V be LeftMod of R; ::_thesis: for A being Subset of V for W being strict Subspace of V st 0. R <> 1. R & A = the carrier of W holds Lin A = W let A be Subset of V; ::_thesis: for W being strict Subspace of V st 0. R <> 1. R & A = the carrier of W holds Lin A = W let W be strict Subspace of V; ::_thesis: ( 0. R <> 1. R & A = the carrier of W implies Lin A = W ) assume that A1: 0. R <> 1. R and A2: A = the carrier of W ; ::_thesis: Lin A = W now__::_thesis:_for_v_being_Vector_of_V_holds_ (_(_v_in_Lin_A_implies_v_in_W_)_&_(_v_in_W_implies_v_in_Lin_A_)_) let v be Vector of V; ::_thesis: ( ( v in Lin A implies v in W ) & ( v in W implies v in Lin A ) ) thus ( v in Lin A implies v in W ) ::_thesis: ( v in W implies v in Lin A ) proof assume v in Lin A ; ::_thesis: v in W then A3: ex l being Linear_Combination of A st v = Sum l by Th4; A is linearly-closed by A2, VECTSP_4:33; then v in the carrier of W by A1, A2, A3, VECTSP_6:14; hence v in W by STRUCT_0:def_5; ::_thesis: verum end; ( v in W iff v in the carrier of W ) by STRUCT_0:def_5; hence ( v in W implies v in Lin A ) by A2, Th5; ::_thesis: verum end; hence Lin A = W by VECTSP_4:30; ::_thesis: verum end; theorem :: MOD_3:9 for R being Ring for V being strict LeftMod of R for A being Subset of V st 0. R <> 1. R & A = the carrier of V holds Lin A = V proof let R be Ring; ::_thesis: for V being strict LeftMod of R for A being Subset of V st 0. R <> 1. R & A = the carrier of V holds Lin A = V let V be strict LeftMod of R; ::_thesis: for A being Subset of V st 0. R <> 1. R & A = the carrier of V holds Lin A = V let A be Subset of V; ::_thesis: ( 0. R <> 1. R & A = the carrier of V implies Lin A = V ) assume that A1: 0. R <> 1. R and A2: A = the carrier of V ; ::_thesis: Lin A = V A = the carrier of ((Omega). V) by A2; hence Lin A = V by A1, Th8; ::_thesis: verum end; theorem Th10: :: MOD_3:10 for R being Ring for V being LeftMod of R for A, B being Subset of V st A c= B holds Lin A is Subspace of Lin B proof let R be Ring; ::_thesis: for V being LeftMod of R for A, B being Subset of V st A c= B holds Lin A is Subspace of Lin B let V be LeftMod of R; ::_thesis: for A, B being Subset of V st A c= B holds Lin A is Subspace of Lin B let A, B be Subset of V; ::_thesis: ( A c= B implies Lin A is Subspace of Lin B ) assume A1: A c= B ; ::_thesis: Lin A is Subspace of Lin B now__::_thesis:_for_v_being_Vector_of_V_st_v_in_Lin_A_holds_ v_in_Lin_B let v be Vector of V; ::_thesis: ( v in Lin A implies v in Lin B ) assume v in Lin A ; ::_thesis: v in Lin B then consider l being Linear_Combination of A such that A2: v = Sum l by Th4; reconsider l = l as Linear_Combination of B by A1, VECTSP_6:4; Sum l = v by A2; hence v in Lin B by Th4; ::_thesis: verum end; hence Lin A is Subspace of Lin B by VECTSP_4:28; ::_thesis: verum end; theorem :: MOD_3:11 for R being Ring for V being LeftMod of R for A, B being Subset of V st Lin A = V & A c= B holds Lin B = V proof let R be Ring; ::_thesis: for V being LeftMod of R for A, B being Subset of V st Lin A = V & A c= B holds Lin B = V let V be LeftMod of R; ::_thesis: for A, B being Subset of V st Lin A = V & A c= B holds Lin B = V let A, B be Subset of V; ::_thesis: ( Lin A = V & A c= B implies Lin B = V ) assume that A1: Lin A = V and A2: A c= B ; ::_thesis: Lin B = V V is Subspace of Lin B by A1, A2, Th10; hence Lin B = V by A1, VECTSP_4:25; ::_thesis: verum end; theorem :: MOD_3:12 for R being Ring for V being LeftMod of R for A, B being Subset of V holds Lin (A \/ B) = (Lin A) + (Lin B) proof let R be Ring; ::_thesis: for V being LeftMod of R for A, B being Subset of V holds Lin (A \/ B) = (Lin A) + (Lin B) let V be LeftMod of R; ::_thesis: for A, B being Subset of V holds Lin (A \/ B) = (Lin A) + (Lin B) let A, B be Subset of V; ::_thesis: Lin (A \/ B) = (Lin A) + (Lin B) now__::_thesis:_for_v_being_Vector_of_V_st_v_in_Lin_(A_\/_B)_holds_ v_in_(Lin_A)_+_(Lin_B) deffunc H1( set ) -> Element of the carrier of R = 0. R; let v be Vector of V; ::_thesis: ( v in Lin (A \/ B) implies v in (Lin A) + (Lin B) ) assume v in Lin (A \/ B) ; ::_thesis: v in (Lin A) + (Lin B) then consider l being Linear_Combination of A \/ B such that A1: v = Sum l by Th4; deffunc H2( set ) -> set = l . $1; set D = (Carrier l) \ A; set C = (Carrier l) /\ A; defpred S1[ set ] means $1 in (Carrier l) /\ A; A2: for x being set st x in the carrier of V holds ( ( S1[x] implies H2(x) in the carrier of R ) & ( not S1[x] implies H1(x) in the carrier of R ) ) proof let x be set ; ::_thesis: ( x in the carrier of V implies ( ( S1[x] implies H2(x) in the carrier of R ) & ( not S1[x] implies H1(x) in the carrier of R ) ) ) assume x in the carrier of V ; ::_thesis: ( ( S1[x] implies H2(x) in the carrier of R ) & ( not S1[x] implies H1(x) in the carrier of R ) ) then reconsider v = x as Vector of V ; for f being Function of the carrier of V, the carrier of R holds f . v in the carrier of R ; hence ( x in (Carrier l) /\ A implies l . x in the carrier of R ) ; ::_thesis: ( not S1[x] implies H1(x) in the carrier of R ) assume not x in (Carrier l) /\ A ; ::_thesis: H1(x) in the carrier of R thus H1(x) in the carrier of R ; ::_thesis: verum end; reconsider C = (Carrier l) /\ A as finite Subset of V ; defpred S2[ set ] means $1 in (Carrier l) \ A; A3: for x being set st x in the carrier of V holds ( ( S2[x] implies H2(x) in the carrier of R ) & ( not S2[x] implies H1(x) in the carrier of R ) ) proof let x be set ; ::_thesis: ( x in the carrier of V implies ( ( S2[x] implies H2(x) in the carrier of R ) & ( not S2[x] implies H1(x) in the carrier of R ) ) ) assume x in the carrier of V ; ::_thesis: ( ( S2[x] implies H2(x) in the carrier of R ) & ( not S2[x] implies H1(x) in the carrier of R ) ) then reconsider v = x as Vector of V ; for g being Function of the carrier of V, the carrier of R holds g . v in the carrier of R ; hence ( x in (Carrier l) \ A implies l . x in the carrier of R ) ; ::_thesis: ( not S2[x] implies H1(x) in the carrier of R ) assume not x in (Carrier l) \ A ; ::_thesis: H1(x) in the carrier of R thus H1(x) in the carrier of R ; ::_thesis: verum end; consider g being Function of the carrier of V, the carrier of R such that A4: for x being set st x in the carrier of V holds ( ( S2[x] implies g . x = H2(x) ) & ( not S2[x] implies g . x = H1(x) ) ) from FUNCT_2:sch_5(A3); reconsider D = (Carrier l) \ A as finite Subset of V ; A5: D c= B proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in D or x in B ) assume x in D ; ::_thesis: x in B then A6: ( x in Carrier l & not x in A ) by XBOOLE_0:def_5; Carrier l c= A \/ B by VECTSP_6:def_4; hence x in B by A6, XBOOLE_0:def_3; ::_thesis: verum end; reconsider g = g as Element of Funcs ( the carrier of V, the carrier of R) by FUNCT_2:8; for u being Vector of V st not u in D holds g . u = 0. R by A4; then reconsider g = g as Linear_Combination of V by VECTSP_6:def_1; Carrier g c= D proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in Carrier g or x in D ) assume x in Carrier g ; ::_thesis: x in D then A7: ex u being Vector of V st ( x = u & g . u <> 0. R ) ; assume not x in D ; ::_thesis: contradiction hence contradiction by A4, A7; ::_thesis: verum end; then Carrier g c= B by A5, XBOOLE_1:1; then reconsider g = g as Linear_Combination of B by VECTSP_6:def_4; consider f being Function of the carrier of V, the carrier of R such that A8: for x being set st x in the carrier of V holds ( ( S1[x] implies f . x = H2(x) ) & ( not S1[x] implies f . x = H1(x) ) ) from FUNCT_2:sch_5(A2); reconsider f = f as Element of Funcs ( the carrier of V, the carrier of R) by FUNCT_2:8; for u being Vector of V st not u in C holds f . u = 0. R by A8; then reconsider f = f as Linear_Combination of V by VECTSP_6:def_1; A9: Carrier f c= C proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in Carrier f or x in C ) assume x in Carrier f ; ::_thesis: x in C then A10: ex u being Vector of V st ( x = u & f . u <> 0. R ) ; assume not x in C ; ::_thesis: contradiction hence contradiction by A8, A10; ::_thesis: verum end; C c= A by XBOOLE_1:17; then Carrier f c= A by A9, XBOOLE_1:1; then reconsider f = f as Linear_Combination of A by VECTSP_6:def_4; l = f + g proof let v be Vector of V; :: according to VECTSP_6:def_7 ::_thesis: l . v = (f + g) . v now__::_thesis:_(f_+_g)_._v_=_l_._v percases ( v in C or not v in C ) ; supposeA11: v in C ; ::_thesis: (f + g) . v = l . v A12: now__::_thesis:_not_v_in_D assume v in D ; ::_thesis: contradiction then not v in A by XBOOLE_0:def_5; hence contradiction by A11, XBOOLE_0:def_4; ::_thesis: verum end; thus (f + g) . v = (f . v) + (g . v) by VECTSP_6:22 .= (l . v) + (g . v) by A8, A11 .= (l . v) + (0. R) by A4, A12 .= l . v by RLVECT_1:4 ; ::_thesis: verum end; supposeA13: not v in C ; ::_thesis: l . v = (f + g) . v now__::_thesis:_(f_+_g)_._v_=_l_._v percases ( v in Carrier l or not v in Carrier l ) ; supposeA14: v in Carrier l ; ::_thesis: (f + g) . v = l . v A15: now__::_thesis:_v_in_D assume not v in D ; ::_thesis: contradiction then ( not v in Carrier l or v in A ) by XBOOLE_0:def_5; hence contradiction by A13, A14, XBOOLE_0:def_4; ::_thesis: verum end; thus (f + g) . v = (f . v) + (g . v) by VECTSP_6:22 .= (0. R) + (g . v) by A8, A13 .= g . v by RLVECT_1:4 .= l . v by A4, A15 ; ::_thesis: verum end; supposeA16: not v in Carrier l ; ::_thesis: (f + g) . v = l . v then A17: not v in D by XBOOLE_0:def_5; A18: not v in C by A16, XBOOLE_0:def_4; thus (f + g) . v = (f . v) + (g . v) by VECTSP_6:22 .= (0. R) + (g . v) by A8, A18 .= (0. R) + (0. R) by A4, A17 .= 0. R by RLVECT_1:4 .= l . v by A16 ; ::_thesis: verum end; end; end; hence l . v = (f + g) . v ; ::_thesis: verum end; end; end; hence l . v = (f + g) . v ; ::_thesis: verum end; then A19: v = (Sum f) + (Sum g) by A1, VECTSP_6:44; ( Sum f in Lin A & Sum g in Lin B ) by Th4; hence v in (Lin A) + (Lin B) by A19, VECTSP_5:1; ::_thesis: verum end; then A20: Lin (A \/ B) is Subspace of (Lin A) + (Lin B) by VECTSP_4:28; ( Lin A is Subspace of Lin (A \/ B) & Lin B is Subspace of Lin (A \/ B) ) by Th10, XBOOLE_1:7; then (Lin A) + (Lin B) is Subspace of Lin (A \/ B) by VECTSP_5:34; hence Lin (A \/ B) = (Lin A) + (Lin B) by A20, VECTSP_4:25; ::_thesis: verum end; theorem :: MOD_3:13 for R being Ring for V being LeftMod of R for A, B being Subset of V holds Lin (A /\ B) is Subspace of (Lin A) /\ (Lin B) proof let R be Ring; ::_thesis: for V being LeftMod of R for A, B being Subset of V holds Lin (A /\ B) is Subspace of (Lin A) /\ (Lin B) let V be LeftMod of R; ::_thesis: for A, B being Subset of V holds Lin (A /\ B) is Subspace of (Lin A) /\ (Lin B) let A, B be Subset of V; ::_thesis: Lin (A /\ B) is Subspace of (Lin A) /\ (Lin B) ( Lin (A /\ B) is Subspace of Lin A & Lin (A /\ B) is Subspace of Lin B ) by Th10, XBOOLE_1:17; hence Lin (A /\ B) is Subspace of (Lin A) /\ (Lin B) by VECTSP_5:19; ::_thesis: verum end; definition let R be Ring; let V be LeftMod of R; let IT be Subset of V; attrIT is base means :Def2: :: MOD_3:def 2 ( IT is linearly-independent & Lin IT = VectSpStr(# the carrier of V, the addF of V, the ZeroF of V, the lmult of V #) ); end; :: deftheorem Def2 defines base MOD_3:def_2_:_ for R being Ring for V being LeftMod of R for IT being Subset of V holds ( IT is base iff ( IT is linearly-independent & Lin IT = VectSpStr(# the carrier of V, the addF of V, the ZeroF of V, the lmult of V #) ) ); definition let R be Ring; let IT be LeftMod of R; attrIT is free means :Def3: :: MOD_3:def 3 ex B being Subset of IT st B is base ; end; :: deftheorem Def3 defines free MOD_3:def_3_:_ for R being Ring for IT being LeftMod of R holds ( IT is free iff ex B being Subset of IT st B is base ); theorem Th14: :: MOD_3:14 for R being Ring for V being LeftMod of R holds (0). V is free proof let R be Ring; ::_thesis: for V being LeftMod of R holds (0). V is free let V be LeftMod of R; ::_thesis: (0). V is free set W = (0). V; reconsider B9 = {} the carrier of V as Subset of ((0). V) by SUBSET_1:1; reconsider V9 = V as Subspace of V by VECTSP_4:24; A1: B9 = {} the carrier of ((0). V) ; then A2: B9 is linearly-independent by LMOD_5:3; (0). V9 = (0). ((0). V) by VECTSP_4:37; then Lin B9 = (0). V by A1, Th6; then B9 is base by A2, Def2; hence (0). V is free by Def3; ::_thesis: verum end; registration let R be Ring; cluster non empty right_complementable strict vector-distributive scalar-distributive scalar-associative scalar-unital Abelian add-associative right_zeroed free for VectSpStr over R; existence ex b1 being LeftMod of R st ( b1 is strict & b1 is free ) proof (0). (LeftModule R) is free by Th14; hence ex b1 being LeftMod of R st ( b1 is strict & b1 is free ) ; ::_thesis: verum end; end; Lm2: for R being Skew-Field for a being Scalar of R for V being LeftMod of R for v being Vector of V st a <> 0. R holds ( (a ") * (a * v) = (1. R) * v & ((a ") * a) * v = (1. R) * v ) proof let R be Skew-Field; ::_thesis: for a being Scalar of R for V being LeftMod of R for v being Vector of V st a <> 0. R holds ( (a ") * (a * v) = (1. R) * v & ((a ") * a) * v = (1. R) * v ) let a be Scalar of R; ::_thesis: for V being LeftMod of R for v being Vector of V st a <> 0. R holds ( (a ") * (a * v) = (1. R) * v & ((a ") * a) * v = (1. R) * v ) let V be LeftMod of R; ::_thesis: for v being Vector of V st a <> 0. R holds ( (a ") * (a * v) = (1. R) * v & ((a ") * a) * v = (1. R) * v ) let v be Vector of V; ::_thesis: ( a <> 0. R implies ( (a ") * (a * v) = (1. R) * v & ((a ") * a) * v = (1. R) * v ) ) assume A1: a <> 0. R ; ::_thesis: ( (a ") * (a * v) = (1. R) * v & ((a ") * a) * v = (1. R) * v ) hence (a ") * (a * v) = v by VECTSP_2:31 .= (1. R) * v by VECTSP_1:def_17 ; ::_thesis: ((a ") * a) * v = (1. R) * v thus ((a ") * a) * v = (1. R) * v by A1, VECTSP_2:9; ::_thesis: verum end; theorem :: MOD_3:15 for R being Skew-Field for V being LeftMod of R for v being Vector of V holds ( {v} is linearly-independent iff v <> 0. V ) proof let R be Skew-Field; ::_thesis: for V being LeftMod of R for v being Vector of V holds ( {v} is linearly-independent iff v <> 0. V ) let V be LeftMod of R; ::_thesis: for v being Vector of V holds ( {v} is linearly-independent iff v <> 0. V ) let v be Vector of V; ::_thesis: ( {v} is linearly-independent iff v <> 0. V ) A1: 0. R <> 1. R ; thus ( {v} is linearly-independent implies v <> 0. V ) ::_thesis: ( v <> 0. V implies {v} is linearly-independent ) proof assume {v} is linearly-independent ; ::_thesis: v <> 0. V then not 0. V in {v} by A1, LMOD_5:2; hence v <> 0. V by TARSKI:def_1; ::_thesis: verum end; assume A2: v <> 0. V ; ::_thesis: {v} is linearly-independent let l be Linear_Combination of {v}; :: according to LMOD_5:def_1 ::_thesis: ( not Sum l = 0. V or Carrier l = {} ) A3: Carrier l c= {v} by VECTSP_6:def_4; assume A4: Sum l = 0. V ; ::_thesis: Carrier l = {} now__::_thesis:_Carrier_l_=_{} percases ( Carrier l = {} or Carrier l = {v} ) by A3, ZFMISC_1:33; suppose Carrier l = {} ; ::_thesis: Carrier l = {} hence Carrier l = {} ; ::_thesis: verum end; supposeA5: Carrier l = {v} ; ::_thesis: Carrier l = {} A6: 0. V = (l . v) * v by A4, VECTSP_6:17; now__::_thesis:_not_v_in_Carrier_l assume v in Carrier l ; ::_thesis: contradiction then l . v <> 0. R by VECTSP_6:2; hence contradiction by A2, A6, VECTSP_2:30; ::_thesis: verum end; hence Carrier l = {} by A5, TARSKI:def_1; ::_thesis: verum end; end; end; hence Carrier l = {} ; ::_thesis: verum end; theorem Th16: :: MOD_3:16 for R being Skew-Field for V being LeftMod of R for v1, v2 being Vector of V holds ( v1 <> v2 & {v1,v2} is linearly-independent iff ( v2 <> 0. V & ( for a being Scalar of R holds v1 <> a * v2 ) ) ) proof let R be Skew-Field; ::_thesis: for V being LeftMod of R for v1, v2 being Vector of V holds ( v1 <> v2 & {v1,v2} is linearly-independent iff ( v2 <> 0. V & ( for a being Scalar of R holds v1 <> a * v2 ) ) ) let V be LeftMod of R; ::_thesis: for v1, v2 being Vector of V holds ( v1 <> v2 & {v1,v2} is linearly-independent iff ( v2 <> 0. V & ( for a being Scalar of R holds v1 <> a * v2 ) ) ) let v1, v2 be Vector of V; ::_thesis: ( v1 <> v2 & {v1,v2} is linearly-independent iff ( v2 <> 0. V & ( for a being Scalar of R holds v1 <> a * v2 ) ) ) A1: 0. R <> 1. R ; thus ( v1 <> v2 & {v1,v2} is linearly-independent implies ( v2 <> 0. V & ( for a being Scalar of R holds v1 <> a * v2 ) ) ) ::_thesis: ( v2 <> 0. V & ( for a being Scalar of R holds v1 <> a * v2 ) implies ( v1 <> v2 & {v1,v2} is linearly-independent ) ) proof deffunc H1( Element of V) -> Element of the carrier of R = 0. R; assume that A2: v1 <> v2 and A3: {v1,v2} is linearly-independent ; ::_thesis: ( v2 <> 0. V & ( for a being Scalar of R holds v1 <> a * v2 ) ) thus v2 <> 0. V by A1, A3, LMOD_5:4; ::_thesis: for a being Scalar of R holds v1 <> a * v2 let a be Scalar of R; ::_thesis: v1 <> a * v2 consider f being Function of the carrier of V, the carrier of R such that A4: ( f . v1 = - (1. R) & f . v2 = a ) and A5: for v being Element of V st v <> v1 & v <> v2 holds f . v = H1(v) from FUNCT_2:sch_7(A2); reconsider f = f as Element of Funcs ( the carrier of V, the carrier of R) by FUNCT_2:8; now__::_thesis:_for_v_being_Vector_of_V_st_not_v_in_{v1,v2}_holds_ f_._v_=_0._R let v be Vector of V; ::_thesis: ( not v in {v1,v2} implies f . v = 0. R ) assume not v in {v1,v2} ; ::_thesis: f . v = 0. R then ( v <> v1 & v <> v2 ) by TARSKI:def_2; hence f . v = 0. R by A5; ::_thesis: verum end; then reconsider f = f as Linear_Combination of V by VECTSP_6:def_1; Carrier f c= {v1,v2} proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in Carrier f or x in {v1,v2} ) assume x in Carrier f ; ::_thesis: x in {v1,v2} then A6: ex u being Vector of V st ( x = u & f . u <> 0. R ) ; assume not x in {v1,v2} ; ::_thesis: contradiction then ( x <> v1 & x <> v2 ) by TARSKI:def_2; hence contradiction by A5, A6; ::_thesis: verum end; then reconsider f = f as Linear_Combination of {v1,v2} by VECTSP_6:def_4; A7: now__::_thesis:_v1_in_Carrier_f assume not v1 in Carrier f ; ::_thesis: contradiction then 0. R = - (1. R) by A4; hence contradiction by Th1; ::_thesis: verum end; set w = a * v2; assume v1 = a * v2 ; ::_thesis: contradiction then Sum f = ((- (1. R)) * (a * v2)) + (a * v2) by A2, A4, VECTSP_6:18 .= (- (a * v2)) + (a * v2) by VECTSP_1:14 .= 0. V by RLVECT_1:5 ; hence contradiction by A3, A7, LMOD_5:def_1; ::_thesis: verum end; assume A8: v2 <> 0. V ; ::_thesis: ( ex a being Scalar of R st not v1 <> a * v2 or ( v1 <> v2 & {v1,v2} is linearly-independent ) ) assume A9: for a being Scalar of R holds v1 <> a * v2 ; ::_thesis: ( v1 <> v2 & {v1,v2} is linearly-independent ) A10: (1. R) * v2 = v2 by VECTSP_1:def_17; hence v1 <> v2 by A9; ::_thesis: {v1,v2} is linearly-independent let l be Linear_Combination of {v1,v2}; :: according to LMOD_5:def_1 ::_thesis: ( not Sum l = 0. V or Carrier l = {} ) assume that A11: Sum l = 0. V and A12: Carrier l <> {} ; ::_thesis: contradiction A13: 0. V = ((l . v1) * v1) + ((l . v2) * v2) by A9, A10, A11, VECTSP_6:18; set x = the Element of Carrier l; Carrier l c= {v1,v2} by VECTSP_6:def_4; then A14: the Element of Carrier l in {v1,v2} by A12, TARSKI:def_3; the Element of Carrier l in Carrier l by A12; then A15: ex u being Vector of V st ( the Element of Carrier l = u & l . u <> 0. R ) ; now__::_thesis:_contradiction percases ( l . v1 <> 0. R or ( l . v2 <> 0. R & l . v1 = 0. R ) ) by A15, A14, TARSKI:def_2; supposeA16: l . v1 <> 0. R ; ::_thesis: contradiction 0. V = ((l . v1) ") * (((l . v1) * v1) + ((l . v2) * v2)) by A13, VECTSP_2:30 .= (((l . v1) ") * ((l . v1) * v1)) + (((l . v1) ") * ((l . v2) * v2)) by VECTSP_1:def_14 .= ((((l . v1) ") * (l . v1)) * v1) + (((l . v1) ") * ((l . v2) * v2)) by VECTSP_1:def_16 .= ((((l . v1) ") * (l . v1)) * v1) + ((((l . v1) ") * (l . v2)) * v2) by VECTSP_1:def_16 .= ((1. R) * v1) + ((((l . v1) ") * (l . v2)) * v2) by A16, Lm2 .= v1 + ((((l . v1) ") * (l . v2)) * v2) by VECTSP_1:def_17 ; then v1 = - ((((l . v1) ") * (l . v2)) * v2) by VECTSP_1:16 .= (- (1. R)) * ((((l . v1) ") * (l . v2)) * v2) by VECTSP_1:14 .= ((- (1. R)) * (((l . v1) ") * (l . v2))) * v2 by VECTSP_1:def_16 ; hence contradiction by A9; ::_thesis: verum end; supposeA17: ( l . v2 <> 0. R & l . v1 = 0. R ) ; ::_thesis: contradiction 0. V = ((l . v2) ") * (((l . v1) * v1) + ((l . v2) * v2)) by A13, VECTSP_2:30 .= (((l . v2) ") * ((l . v1) * v1)) + (((l . v2) ") * ((l . v2) * v2)) by VECTSP_1:def_14 .= ((((l . v2) ") * (l . v1)) * v1) + (((l . v2) ") * ((l . v2) * v2)) by VECTSP_1:def_16 .= ((((l . v2) ") * (l . v1)) * v1) + ((1. R) * v2) by A17, Lm2 .= ((((l . v2) ") * (l . v1)) * v1) + v2 by VECTSP_1:def_17 .= ((0. R) * v1) + v2 by A17, VECTSP_1:6 .= (0. V) + v2 by VECTSP_2:30 .= v2 by RLVECT_1:def_4 ; hence contradiction by A8; ::_thesis: verum end; end; end; hence contradiction ; ::_thesis: verum end; theorem :: MOD_3:17 for R being Skew-Field for V being LeftMod of R for v1, v2 being Vector of V holds ( ( v1 <> v2 & {v1,v2} is linearly-independent ) iff for a, b being Scalar of R st (a * v1) + (b * v2) = 0. V holds ( a = 0. R & b = 0. R ) ) proof let R be Skew-Field; ::_thesis: for V being LeftMod of R for v1, v2 being Vector of V holds ( ( v1 <> v2 & {v1,v2} is linearly-independent ) iff for a, b being Scalar of R st (a * v1) + (b * v2) = 0. V holds ( a = 0. R & b = 0. R ) ) let V be LeftMod of R; ::_thesis: for v1, v2 being Vector of V holds ( ( v1 <> v2 & {v1,v2} is linearly-independent ) iff for a, b being Scalar of R st (a * v1) + (b * v2) = 0. V holds ( a = 0. R & b = 0. R ) ) let v1, v2 be Vector of V; ::_thesis: ( ( v1 <> v2 & {v1,v2} is linearly-independent ) iff for a, b being Scalar of R st (a * v1) + (b * v2) = 0. V holds ( a = 0. R & b = 0. R ) ) thus ( v1 <> v2 & {v1,v2} is linearly-independent implies for a, b being Scalar of R st (a * v1) + (b * v2) = 0. V holds ( a = 0. R & b = 0. R ) ) ::_thesis: ( ( for a, b being Scalar of R st (a * v1) + (b * v2) = 0. V holds ( a = 0. R & b = 0. R ) ) implies ( v1 <> v2 & {v1,v2} is linearly-independent ) ) proof assume A1: ( v1 <> v2 & {v1,v2} is linearly-independent ) ; ::_thesis: for a, b being Scalar of R st (a * v1) + (b * v2) = 0. V holds ( a = 0. R & b = 0. R ) let a, b be Scalar of R; ::_thesis: ( (a * v1) + (b * v2) = 0. V implies ( a = 0. R & b = 0. R ) ) assume that A2: (a * v1) + (b * v2) = 0. V and A3: ( a <> 0. R or b <> 0. R ) ; ::_thesis: contradiction now__::_thesis:_contradiction percases ( a <> 0. R or b <> 0. R ) by A3; supposeA4: a <> 0. R ; ::_thesis: contradiction 0. V = (a ") * ((a * v1) + (b * v2)) by A2, VECTSP_2:30 .= ((a ") * (a * v1)) + ((a ") * (b * v2)) by VECTSP_1:def_14 .= (((a ") * a) * v1) + ((a ") * (b * v2)) by VECTSP_1:def_16 .= (((a ") * a) * v1) + (((a ") * b) * v2) by VECTSP_1:def_16 .= ((1. R) * v1) + (((a ") * b) * v2) by A4, Lm2 .= v1 + (((a ") * b) * v2) by VECTSP_1:def_17 ; then v1 = - (((a ") * b) * v2) by VECTSP_1:16 .= (- (1. R)) * (((a ") * b) * v2) by VECTSP_1:14 .= ((- (1. R)) * ((a ") * b)) * v2 by VECTSP_1:def_16 ; hence contradiction by A1, Th16; ::_thesis: verum end; supposeA5: b <> 0. R ; ::_thesis: contradiction 0. V = (b ") * ((a * v1) + (b * v2)) by A2, VECTSP_2:30 .= ((b ") * (a * v1)) + ((b ") * (b * v2)) by VECTSP_1:def_14 .= (((b ") * a) * v1) + ((b ") * (b * v2)) by VECTSP_1:def_16 .= (((b ") * a) * v1) + ((1. R) * v2) by A5, Lm2 .= (((b ") * a) * v1) + v2 by VECTSP_1:def_17 ; then v2 = - (((b ") * a) * v1) by VECTSP_1:16 .= (- (1. R)) * (((b ") * a) * v1) by VECTSP_1:14 .= ((- (1. R)) * ((b ") * a)) * v1 by VECTSP_1:def_16 ; hence contradiction by A1, Th16; ::_thesis: verum end; end; end; hence contradiction ; ::_thesis: verum end; assume A6: for a, b being Scalar of R st (a * v1) + (b * v2) = 0. V holds ( a = 0. R & b = 0. R ) ; ::_thesis: ( v1 <> v2 & {v1,v2} is linearly-independent ) A7: now__::_thesis:_for_a_being_Scalar_of_R_holds_not_v1_=_a_*_v2 let a be Scalar of R; ::_thesis: not v1 = a * v2 assume v1 = a * v2 ; ::_thesis: contradiction then v1 = (0. V) + (a * v2) by RLVECT_1:def_4; then 0. V = v1 - (a * v2) by RLSUB_2:61 .= v1 + ((- a) * v2) by VECTSP_1:21 .= ((1. R) * v1) + ((- a) * v2) by VECTSP_1:def_17 ; hence contradiction by A6; ::_thesis: verum end; now__::_thesis:_not_v2_=_0._V assume A8: v2 = 0. V ; ::_thesis: contradiction 0. V = (0. V) + (0. V) by RLVECT_1:def_4 .= ((0. R) * v1) + (0. V) by VECTSP_2:30 .= ((0. R) * v1) + ((1. R) * v2) by A8, VECTSP_2:30 ; hence contradiction by A6; ::_thesis: verum end; hence ( v1 <> v2 & {v1,v2} is linearly-independent ) by A7, Th16; ::_thesis: verum end; theorem Th18: :: MOD_3:18 for R being Skew-Field for V being LeftMod of R for A being Subset of V st A is linearly-independent holds ex B being Subset of V st ( A c= B & B is base ) proof let R be Skew-Field; ::_thesis: for V being LeftMod of R for A being Subset of V st A is linearly-independent holds ex B being Subset of V st ( A c= B & B is base ) let V be LeftMod of R; ::_thesis: for A being Subset of V st A is linearly-independent holds ex B being Subset of V st ( A c= B & B is base ) let A be Subset of V; ::_thesis: ( A is linearly-independent implies ex B being Subset of V st ( A c= B & B is base ) ) defpred S1[ set ] means ex B being Subset of V st ( B = $1 & A c= B & B is linearly-independent ); consider Q being set such that A1: for Z being set holds ( Z in Q iff ( Z in bool the carrier of V & S1[Z] ) ) from XBOOLE_0:sch_1(); A2: now__::_thesis:_for_Z_being_set_st_Z_<>_{}_&_Z_c=_Q_&_Z_is_c=-linear_holds_ union_Z_in_Q let Z be set ; ::_thesis: ( Z <> {} & Z c= Q & Z is c=-linear implies union Z in Q ) assume that A3: Z <> {} and A4: Z c= Q and A5: Z is c=-linear ; ::_thesis: union Z in Q set W = union Z; union Z c= the carrier of V proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in union Z or x in the carrier of V ) assume x in union Z ; ::_thesis: x in the carrier of V then consider X being set such that A6: x in X and A7: X in Z by TARSKI:def_4; X in bool the carrier of V by A1, A4, A7; hence x in the carrier of V by A6; ::_thesis: verum end; then reconsider W = union Z as Subset of V ; A8: W is linearly-independent proof deffunc H1( set ) -> set = { C where C is Subset of V : ( $1 in C & C in Z ) } ; let l be Linear_Combination of W; :: according to LMOD_5:def_1 ::_thesis: ( not Sum l = 0. V or Carrier l = {} ) assume that A9: Sum l = 0. V and A10: Carrier l <> {} ; ::_thesis: contradiction consider f being Function such that A11: dom f = Carrier l and A12: for x being set st x in Carrier l holds f . x = H1(x) from FUNCT_1:sch_3(); reconsider M = rng f as non empty set by A10, A11, RELAT_1:42; set F = the Choice_Function of M; set S = rng the Choice_Function of M; A13: now__::_thesis:_not_{}_in_M assume {} in M ; ::_thesis: contradiction then consider x being set such that A14: x in dom f and A15: f . x = {} by FUNCT_1:def_3; Carrier l c= W by VECTSP_6:def_4; then consider X being set such that A16: x in X and A17: X in Z by A11, A14, TARSKI:def_4; reconsider X = X as Subset of V by A1, A4, A17; X in { C where C is Subset of V : ( x in C & C in Z ) } by A16, A17; hence contradiction by A11, A12, A14, A15; ::_thesis: verum end; then A18: dom the Choice_Function of M = M by RLVECT_3:28; then dom the Choice_Function of M is finite by A11, FINSET_1:8; then A19: rng the Choice_Function of M is finite by FINSET_1:8; A20: now__::_thesis:_for_X_being_set_st_X_in_rng_the_Choice_Function_of_M_holds_ X_in_Z let X be set ; ::_thesis: ( X in rng the Choice_Function of M implies X in Z ) assume X in rng the Choice_Function of M ; ::_thesis: X in Z then consider x being set such that A21: x in dom the Choice_Function of M and A22: the Choice_Function of M . x = X by FUNCT_1:def_3; consider y being set such that A23: ( y in dom f & f . y = x ) by A18, A21, FUNCT_1:def_3; A24: x = { C where C is Subset of V : ( y in C & C in Z ) } by A11, A12, A23; X in x by A13, A18, A21, A22, ORDERS_1:def_1; then ex C being Subset of V st ( C = X & y in C & C in Z ) by A24; hence X in Z ; ::_thesis: verum end; A25: now__::_thesis:_for_X,_Y_being_set_st_X_in_rng_the_Choice_Function_of_M_&_Y_in_rng_the_Choice_Function_of_M_&_not_X_c=_Y_holds_ Y_c=_X let X, Y be set ; ::_thesis: ( X in rng the Choice_Function of M & Y in rng the Choice_Function of M & not X c= Y implies Y c= X ) assume ( X in rng the Choice_Function of M & Y in rng the Choice_Function of M ) ; ::_thesis: ( X c= Y or Y c= X ) then ( X in Z & Y in Z ) by A20; then X,Y are_c=-comparable by A5, ORDINAL1:def_8; hence ( X c= Y or Y c= X ) by XBOOLE_0:def_9; ::_thesis: verum end; rng the Choice_Function of M <> {} by A18, RELAT_1:42; then union (rng the Choice_Function of M) in rng the Choice_Function of M by A25, A19, CARD_2:62; then union (rng the Choice_Function of M) in Z by A20; then consider B being Subset of V such that A26: B = union (rng the Choice_Function of M) and A c= B and A27: B is linearly-independent by A1, A4; Carrier l c= union (rng the Choice_Function of M) proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in Carrier l or x in union (rng the Choice_Function of M) ) set X = f . x; assume A28: x in Carrier l ; ::_thesis: x in union (rng the Choice_Function of M) then A29: f . x = { C where C is Subset of V : ( x in C & C in Z ) } by A12; A30: f . x in M by A11, A28, FUNCT_1:def_3; then the Choice_Function of M . (f . x) in f . x by A13, ORDERS_1:def_1; then A31: ex C being Subset of V st ( the Choice_Function of M . (f . x) = C & x in C & C in Z ) by A29; the Choice_Function of M . (f . x) in rng the Choice_Function of M by A18, A30, FUNCT_1:def_3; hence x in union (rng the Choice_Function of M) by A31, TARSKI:def_4; ::_thesis: verum end; then l is Linear_Combination of B by A26, VECTSP_6:def_4; hence contradiction by A9, A10, A27, LMOD_5:def_1; ::_thesis: verum end; set x = the Element of Z; the Element of Z in Q by A3, A4, TARSKI:def_3; then A32: ex B being Subset of V st ( B = the Element of Z & A c= B & B is linearly-independent ) by A1; the Element of Z c= W by A3, ZFMISC_1:74; then A c= W by A32, XBOOLE_1:1; hence union Z in Q by A1, A8; ::_thesis: verum end; assume A is linearly-independent ; ::_thesis: ex B being Subset of V st ( A c= B & B is base ) then Q <> {} by A1; then consider X being set such that A33: X in Q and A34: for Z being set st Z in Q & Z <> X holds not X c= Z by A2, ORDERS_1:67; consider B being Subset of V such that A35: B = X and A36: A c= B and A37: B is linearly-independent by A1, A33; take B ; ::_thesis: ( A c= B & B is base ) thus ( A c= B & B is linearly-independent ) by A36, A37; :: according to MOD_3:def_2 ::_thesis: Lin B = VectSpStr(# the carrier of V, the addF of V, the ZeroF of V, the lmult of V #) assume Lin B <> VectSpStr(# the carrier of V, the addF of V, the ZeroF of V, the lmult of V #) ; ::_thesis: contradiction then consider v being Vector of V such that A38: ( ( v in Lin B & not v in (Omega). V ) or ( v in (Omega). V & not v in Lin B ) ) by VECTSP_4:30; A39: B \/ {v} is linearly-independent proof let l be Linear_Combination of B \/ {v}; :: according to LMOD_5:def_1 ::_thesis: ( not Sum l = 0. V or Carrier l = {} ) assume A40: Sum l = 0. V ; ::_thesis: Carrier l = {} now__::_thesis:_Carrier_l_=_{} percases ( v in Carrier l or not v in Carrier l ) ; suppose v in Carrier l ; ::_thesis: Carrier l = {} then l . v <> 0. R by VECTSP_6:2; then - (l . v) <> 0. R by Lm1; then A41: ((- (l . v)) ") * ((- (l . v)) * v) = (1. R) * v by Lm2 .= v by VECTSP_1:def_17 ; deffunc H1( Vector of V) -> Element of the carrier of R = l . $1; consider f being Function of the carrier of V, the carrier of R such that A42: f . v = 0. R and A43: for u being Vector of V st u <> v holds f . u = H1(u) from FUNCT_2:sch_6(); reconsider f = f as Element of Funcs ( the carrier of V, the carrier of R) by FUNCT_2:8; now__::_thesis:_for_u_being_Vector_of_V_st_not_u_in_(Carrier_l)_\_{v}_holds_ f_._u_=_0._R let u be Vector of V; ::_thesis: ( not u in (Carrier l) \ {v} implies f . u = 0. R ) assume not u in (Carrier l) \ {v} ; ::_thesis: f . u = 0. R then ( not u in Carrier l or u in {v} ) by XBOOLE_0:def_5; then ( ( l . u = 0. R & u <> v ) or u = v ) by TARSKI:def_1; hence f . u = 0. R by A42, A43; ::_thesis: verum end; then reconsider f = f as Linear_Combination of V by VECTSP_6:def_1; Carrier f c= B proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in Carrier f or x in B ) A44: Carrier l c= B \/ {v} by VECTSP_6:def_4; assume x in Carrier f ; ::_thesis: x in B then consider u being Vector of V such that A45: u = x and A46: f . u <> 0. R ; f . u = l . u by A42, A43, A46; then u in Carrier l by A46; then ( u in B or u in {v} ) by A44, XBOOLE_0:def_3; hence x in B by A42, A45, A46, TARSKI:def_1; ::_thesis: verum end; then reconsider f = f as Linear_Combination of B by VECTSP_6:def_4; deffunc H2( Vector of V) -> Element of the carrier of R = 0. R; consider g being Function of the carrier of V, the carrier of R such that A47: g . v = - (l . v) and A48: for u being Vector of V st u <> v holds g . u = H2(u) from FUNCT_2:sch_6(); reconsider g = g as Element of Funcs ( the carrier of V, the carrier of R) by FUNCT_2:8; now__::_thesis:_for_u_being_Vector_of_V_st_not_u_in_{v}_holds_ g_._u_=_0._R let u be Vector of V; ::_thesis: ( not u in {v} implies g . u = 0. R ) assume not u in {v} ; ::_thesis: g . u = 0. R then u <> v by TARSKI:def_1; hence g . u = 0. R by A48; ::_thesis: verum end; then reconsider g = g as Linear_Combination of V by VECTSP_6:def_1; Carrier g c= {v} proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in Carrier g or x in {v} ) assume x in Carrier g ; ::_thesis: x in {v} then ex u being Vector of V st ( x = u & g . u <> 0. R ) ; then x = v by A48; hence x in {v} by TARSKI:def_1; ::_thesis: verum end; then reconsider g = g as Linear_Combination of {v} by VECTSP_6:def_4; f - g = l proof let u be Vector of V; :: according to VECTSP_6:def_7 ::_thesis: (f - g) . u = l . u now__::_thesis:_(f_-_g)_._u_=_l_._u percases ( v = u or v <> u ) ; supposeA49: v = u ; ::_thesis: (f - g) . u = l . u thus (f - g) . u = (f . u) - (g . u) by VECTSP_6:40 .= (0. R) + (- (- (l . v))) by A42, A47, A49, RLVECT_1:def_11 .= (l . v) + (0. R) by RLVECT_1:17 .= l . u by A49, RLVECT_1:4 ; ::_thesis: verum end; supposeA50: v <> u ; ::_thesis: (f - g) . u = l . u thus (f - g) . u = (f . u) - (g . u) by VECTSP_6:40 .= (l . u) - (g . u) by A43, A50 .= (l . u) - (0. R) by A48, A50 .= l . u by RLVECT_1:13 ; ::_thesis: verum end; end; end; hence (f - g) . u = l . u ; ::_thesis: verum end; then A51: 0. V = (Sum f) - (Sum g) by A40, VECTSP_6:47; Sum g = (- (l . v)) * v by A47, VECTSP_6:17; then Sum f = (- (l . v)) * v by A51, VECTSP_1:19; then (- (l . v)) * v in Lin B by Th4; hence Carrier l = {} by A38, A41, STRUCT_0:def_5, VECTSP_4:21; ::_thesis: verum end; supposeA52: not v in Carrier l ; ::_thesis: Carrier l = {} Carrier l c= B proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in Carrier l or x in B ) assume A53: x in Carrier l ; ::_thesis: x in B Carrier l c= B \/ {v} by VECTSP_6:def_4; then ( x in B or x in {v} ) by A53, XBOOLE_0:def_3; hence x in B by A52, A53, TARSKI:def_1; ::_thesis: verum end; then l is Linear_Combination of B by VECTSP_6:def_4; hence Carrier l = {} by A37, A40, LMOD_5:def_1; ::_thesis: verum end; end; end; hence Carrier l = {} ; ::_thesis: verum end; v in {v} by TARSKI:def_1; then A54: v in B \/ {v} by XBOOLE_0:def_3; A55: not v in B by A38, Th5, STRUCT_0:def_5; B c= B \/ {v} by XBOOLE_1:7; then A c= B \/ {v} by A36, XBOOLE_1:1; then B \/ {v} in Q by A1, A39; hence contradiction by A34, A35, A54, A55, XBOOLE_1:7; ::_thesis: verum end; theorem Th19: :: MOD_3:19 for R being Skew-Field for V being LeftMod of R for A being Subset of V st Lin A = V holds ex B being Subset of V st ( B c= A & B is base ) proof let R be Skew-Field; ::_thesis: for V being LeftMod of R for A being Subset of V st Lin A = V holds ex B being Subset of V st ( B c= A & B is base ) let V be LeftMod of R; ::_thesis: for A being Subset of V st Lin A = V holds ex B being Subset of V st ( B c= A & B is base ) let A be Subset of V; ::_thesis: ( Lin A = V implies ex B being Subset of V st ( B c= A & B is base ) ) A1: 0. R <> 1. R ; defpred S1[ set ] means ex B being Subset of V st ( B = $1 & B c= A & B is linearly-independent ); assume A2: Lin A = V ; ::_thesis: ex B being Subset of V st ( B c= A & B is base ) consider Q being set such that A3: for Z being set holds ( Z in Q iff ( Z in bool the carrier of V & S1[Z] ) ) from XBOOLE_0:sch_1(); A4: now__::_thesis:_for_Z_being_set_st_Z_<>_{}_&_Z_c=_Q_&_Z_is_c=-linear_holds_ union_Z_in_Q let Z be set ; ::_thesis: ( Z <> {} & Z c= Q & Z is c=-linear implies union Z in Q ) assume that Z <> {} and A5: Z c= Q and A6: Z is c=-linear ; ::_thesis: union Z in Q set W = union Z; union Z c= the carrier of V proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in union Z or x in the carrier of V ) assume x in union Z ; ::_thesis: x in the carrier of V then consider X being set such that A7: x in X and A8: X in Z by TARSKI:def_4; X in bool the carrier of V by A3, A5, A8; hence x in the carrier of V by A7; ::_thesis: verum end; then reconsider W = union Z as Subset of V ; A9: W is linearly-independent proof deffunc H1( set ) -> set = { C where C is Subset of V : ( $1 in C & C in Z ) } ; let l be Linear_Combination of W; :: according to LMOD_5:def_1 ::_thesis: ( not Sum l = 0. V or Carrier l = {} ) assume that A10: Sum l = 0. V and A11: Carrier l <> {} ; ::_thesis: contradiction consider f being Function such that A12: dom f = Carrier l and A13: for x being set st x in Carrier l holds f . x = H1(x) from FUNCT_1:sch_3(); reconsider M = rng f as non empty set by A11, A12, RELAT_1:42; set F = the Choice_Function of M; set S = rng the Choice_Function of M; A14: now__::_thesis:_not_{}_in_M assume {} in M ; ::_thesis: contradiction then consider x being set such that A15: x in dom f and A16: f . x = {} by FUNCT_1:def_3; Carrier l c= W by VECTSP_6:def_4; then consider X being set such that A17: x in X and A18: X in Z by A12, A15, TARSKI:def_4; reconsider X = X as Subset of V by A3, A5, A18; X in { C where C is Subset of V : ( x in C & C in Z ) } by A17, A18; hence contradiction by A12, A13, A15, A16; ::_thesis: verum end; then A19: dom the Choice_Function of M = M by RLVECT_3:28; then dom the Choice_Function of M is finite by A12, FINSET_1:8; then A20: rng the Choice_Function of M is finite by FINSET_1:8; A21: now__::_thesis:_for_X_being_set_st_X_in_rng_the_Choice_Function_of_M_holds_ X_in_Z let X be set ; ::_thesis: ( X in rng the Choice_Function of M implies X in Z ) assume X in rng the Choice_Function of M ; ::_thesis: X in Z then consider x being set such that A22: x in dom the Choice_Function of M and A23: the Choice_Function of M . x = X by FUNCT_1:def_3; consider y being set such that A24: ( y in dom f & f . y = x ) by A19, A22, FUNCT_1:def_3; A25: x = { C where C is Subset of V : ( y in C & C in Z ) } by A12, A13, A24; X in x by A14, A19, A22, A23, ORDERS_1:def_1; then ex C being Subset of V st ( C = X & y in C & C in Z ) by A25; hence X in Z ; ::_thesis: verum end; A26: now__::_thesis:_for_X,_Y_being_set_st_X_in_rng_the_Choice_Function_of_M_&_Y_in_rng_the_Choice_Function_of_M_&_not_X_c=_Y_holds_ Y_c=_X let X, Y be set ; ::_thesis: ( X in rng the Choice_Function of M & Y in rng the Choice_Function of M & not X c= Y implies Y c= X ) assume ( X in rng the Choice_Function of M & Y in rng the Choice_Function of M ) ; ::_thesis: ( X c= Y or Y c= X ) then ( X in Z & Y in Z ) by A21; then X,Y are_c=-comparable by A6, ORDINAL1:def_8; hence ( X c= Y or Y c= X ) by XBOOLE_0:def_9; ::_thesis: verum end; rng the Choice_Function of M <> {} by A19, RELAT_1:42; then union (rng the Choice_Function of M) in rng the Choice_Function of M by A26, A20, CARD_2:62; then union (rng the Choice_Function of M) in Z by A21; then consider B being Subset of V such that A27: B = union (rng the Choice_Function of M) and B c= A and A28: B is linearly-independent by A3, A5; Carrier l c= union (rng the Choice_Function of M) proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in Carrier l or x in union (rng the Choice_Function of M) ) set X = f . x; assume A29: x in Carrier l ; ::_thesis: x in union (rng the Choice_Function of M) then A30: f . x = { C where C is Subset of V : ( x in C & C in Z ) } by A13; A31: f . x in M by A12, A29, FUNCT_1:def_3; then the Choice_Function of M . (f . x) in f . x by A14, ORDERS_1:def_1; then A32: ex C being Subset of V st ( the Choice_Function of M . (f . x) = C & x in C & C in Z ) by A30; the Choice_Function of M . (f . x) in rng the Choice_Function of M by A19, A31, FUNCT_1:def_3; hence x in union (rng the Choice_Function of M) by A32, TARSKI:def_4; ::_thesis: verum end; then l is Linear_Combination of B by A27, VECTSP_6:def_4; hence contradiction by A10, A11, A28, LMOD_5:def_1; ::_thesis: verum end; W c= A proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in W or x in A ) assume x in W ; ::_thesis: x in A then consider X being set such that A33: x in X and A34: X in Z by TARSKI:def_4; ex B being Subset of V st ( B = X & B c= A & B is linearly-independent ) by A3, A5, A34; hence x in A by A33; ::_thesis: verum end; hence union Z in Q by A3, A9; ::_thesis: verum end; ( {} the carrier of V c= A & {} the carrier of V is linearly-independent ) by LMOD_5:3, XBOOLE_1:2; then Q <> {} by A3; then consider X being set such that A35: X in Q and A36: for Z being set st Z in Q & Z <> X holds not X c= Z by A4, ORDERS_1:67; consider B being Subset of V such that A37: B = X and A38: B c= A and A39: B is linearly-independent by A3, A35; take B ; ::_thesis: ( B c= A & B is base ) thus ( B c= A & B is linearly-independent ) by A38, A39; :: according to MOD_3:def_2 ::_thesis: Lin B = VectSpStr(# the carrier of V, the addF of V, the ZeroF of V, the lmult of V #) assume A40: Lin B <> VectSpStr(# the carrier of V, the addF of V, the ZeroF of V, the lmult of V #) ; ::_thesis: contradiction now__::_thesis:_ex_v_being_Vector_of_V_st_ (_v_in_A_&_not_v_in_Lin_B_) assume A41: for v being Vector of V st v in A holds v in Lin B ; ::_thesis: contradiction now__::_thesis:_for_v_being_Vector_of_V_st_v_in_Lin_A_holds_ v_in_Lin_B reconsider F = the carrier of (Lin B) as Subset of V by VECTSP_4:def_2; let v be Vector of V; ::_thesis: ( v in Lin A implies v in Lin B ) assume v in Lin A ; ::_thesis: v in Lin B then consider l being Linear_Combination of A such that A42: v = Sum l by Th4; Carrier l c= the carrier of (Lin B) proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in Carrier l or x in the carrier of (Lin B) ) assume A43: x in Carrier l ; ::_thesis: x in the carrier of (Lin B) then reconsider a = x as Vector of V ; Carrier l c= A by VECTSP_6:def_4; then a in Lin B by A41, A43; hence x in the carrier of (Lin B) by STRUCT_0:def_5; ::_thesis: verum end; then reconsider l = l as Linear_Combination of F by VECTSP_6:def_4; Sum l = v by A42; then v in Lin F by Th4; hence v in Lin B by A1, Th8; ::_thesis: verum end; then Lin A is Subspace of Lin B by VECTSP_4:28; hence contradiction by A2, A40, VECTSP_4:25; ::_thesis: verum end; then consider v being Vector of V such that A44: v in A and A45: not v in Lin B ; A46: B \/ {v} is linearly-independent proof let l be Linear_Combination of B \/ {v}; :: according to LMOD_5:def_1 ::_thesis: ( not Sum l = 0. V or Carrier l = {} ) assume A47: Sum l = 0. V ; ::_thesis: Carrier l = {} now__::_thesis:_Carrier_l_=_{} percases ( v in Carrier l or not v in Carrier l ) ; suppose v in Carrier l ; ::_thesis: Carrier l = {} then l . v <> 0. R by VECTSP_6:2; then - (l . v) <> 0. R by Lm1; then A48: ((- (l . v)) ") * ((- (l . v)) * v) = (1. R) * v by Lm2 .= v by VECTSP_1:def_17 ; deffunc H1( Vector of V) -> Element of the carrier of R = l . $1; consider f being Function of the carrier of V, the carrier of R such that A49: f . v = 0. R and A50: for u being Vector of V st u <> v holds f . u = H1(u) from FUNCT_2:sch_6(); reconsider f = f as Element of Funcs ( the carrier of V, the carrier of R) by FUNCT_2:8; now__::_thesis:_for_u_being_Vector_of_V_st_not_u_in_(Carrier_l)_\_{v}_holds_ f_._u_=_0._R let u be Vector of V; ::_thesis: ( not u in (Carrier l) \ {v} implies f . u = 0. R ) assume not u in (Carrier l) \ {v} ; ::_thesis: f . u = 0. R then ( not u in Carrier l or u in {v} ) by XBOOLE_0:def_5; then ( ( l . u = 0. R & u <> v ) or u = v ) by TARSKI:def_1; hence f . u = 0. R by A49, A50; ::_thesis: verum end; then reconsider f = f as Linear_Combination of V by VECTSP_6:def_1; Carrier f c= B proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in Carrier f or x in B ) A51: Carrier l c= B \/ {v} by VECTSP_6:def_4; assume x in Carrier f ; ::_thesis: x in B then consider u being Vector of V such that A52: u = x and A53: f . u <> 0. R ; f . u = l . u by A49, A50, A53; then u in Carrier l by A53; then ( u in B or u in {v} ) by A51, XBOOLE_0:def_3; hence x in B by A49, A52, A53, TARSKI:def_1; ::_thesis: verum end; then reconsider f = f as Linear_Combination of B by VECTSP_6:def_4; deffunc H2( Vector of V) -> Element of the carrier of R = 0. R; consider g being Function of the carrier of V, the carrier of R such that A54: g . v = - (l . v) and A55: for u being Vector of V st u <> v holds g . u = H2(u) from FUNCT_2:sch_6(); reconsider g = g as Element of Funcs ( the carrier of V, the carrier of R) by FUNCT_2:8; now__::_thesis:_for_u_being_Vector_of_V_st_not_u_in_{v}_holds_ g_._u_=_0._R let u be Vector of V; ::_thesis: ( not u in {v} implies g . u = 0. R ) assume not u in {v} ; ::_thesis: g . u = 0. R then u <> v by TARSKI:def_1; hence g . u = 0. R by A55; ::_thesis: verum end; then reconsider g = g as Linear_Combination of V by VECTSP_6:def_1; Carrier g c= {v} proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in Carrier g or x in {v} ) assume x in Carrier g ; ::_thesis: x in {v} then ex u being Vector of V st ( x = u & g . u <> 0. R ) ; then x = v by A55; hence x in {v} by TARSKI:def_1; ::_thesis: verum end; then reconsider g = g as Linear_Combination of {v} by VECTSP_6:def_4; f - g = l proof let u be Vector of V; :: according to VECTSP_6:def_7 ::_thesis: (f - g) . u = l . u now__::_thesis:_(f_-_g)_._u_=_l_._u percases ( v = u or v <> u ) ; supposeA56: v = u ; ::_thesis: (f - g) . u = l . u thus (f - g) . u = (f . u) - (g . u) by VECTSP_6:40 .= (0. R) + (- (- (l . v))) by A49, A54, A56, RLVECT_1:def_11 .= (l . v) + (0. R) by RLVECT_1:17 .= l . u by A56, RLVECT_1:4 ; ::_thesis: verum end; supposeA57: v <> u ; ::_thesis: (f - g) . u = l . u thus (f - g) . u = (f . u) - (g . u) by VECTSP_6:40 .= (l . u) - (g . u) by A50, A57 .= (l . u) - (0. R) by A55, A57 .= l . u by RLVECT_1:13 ; ::_thesis: verum end; end; end; hence (f - g) . u = l . u ; ::_thesis: verum end; then A58: 0. V = (Sum f) - (Sum g) by A47, VECTSP_6:47; Sum g = (- (l . v)) * v by A54, VECTSP_6:17; then Sum f = (- (l . v)) * v by A58, VECTSP_1:19; then (- (l . v)) * v in Lin B by Th4; hence Carrier l = {} by A45, A48, VECTSP_4:21; ::_thesis: verum end; supposeA59: not v in Carrier l ; ::_thesis: Carrier l = {} Carrier l c= B proof let x be set ; :: according to TARSKI:def_3 ::_thesis: ( not x in Carrier l or x in B ) assume A60: x in Carrier l ; ::_thesis: x in B Carrier l c= B \/ {v} by VECTSP_6:def_4; then ( x in B or x in {v} ) by A60, XBOOLE_0:def_3; hence x in B by A59, A60, TARSKI:def_1; ::_thesis: verum end; then l is Linear_Combination of B by VECTSP_6:def_4; hence Carrier l = {} by A39, A47, LMOD_5:def_1; ::_thesis: verum end; end; end; hence Carrier l = {} ; ::_thesis: verum end; {v} c= A by A44, ZFMISC_1:31; then B \/ {v} c= A by A38, XBOOLE_1:8; then A61: B \/ {v} in Q by A3, A46; v in {v} by TARSKI:def_1; then A62: v in B \/ {v} by XBOOLE_0:def_3; not v in B by A45, Th5; hence contradiction by A36, A37, A62, A61, XBOOLE_1:7; ::_thesis: verum end; Lm3: for R being Skew-Field for V being LeftMod of R ex B being Subset of V st B is base proof let R be Skew-Field; ::_thesis: for V being LeftMod of R ex B being Subset of V st B is base let V be LeftMod of R; ::_thesis: ex B being Subset of V st B is base ex B being Subset of V st ( {} the carrier of V c= B & B is base ) by Th18, LMOD_5:3; hence ex B being Subset of V st B is base ; ::_thesis: verum end; theorem :: MOD_3:20 for R being Skew-Field for V being LeftMod of R holds V is free proof let R be Skew-Field; ::_thesis: for V being LeftMod of R holds V is free let V be LeftMod of R; ::_thesis: V is free ex B being Subset of V st B is base by Lm3; hence V is free by Def3; ::_thesis: verum end; definition let R be Skew-Field; let V be LeftMod of R; mode Basis of V -> Subset of V means :Def4: :: MOD_3:def 4 it is base ; existence ex b1 being Subset of V st b1 is base by Lm3; end; :: deftheorem Def4 defines Basis MOD_3:def_4_:_ for R being Skew-Field for V being LeftMod of R for b3 being Subset of V holds ( b3 is Basis of V iff b3 is base ); theorem :: MOD_3:21 for R being Skew-Field for V being LeftMod of R for A being Subset of V st A is linearly-independent holds ex I being Basis of V st A c= I proof let R be Skew-Field; ::_thesis: for V being LeftMod of R for A being Subset of V st A is linearly-independent holds ex I being Basis of V st A c= I let V be LeftMod of R; ::_thesis: for A being Subset of V st A is linearly-independent holds ex I being Basis of V st A c= I let A be Subset of V; ::_thesis: ( A is linearly-independent implies ex I being Basis of V st A c= I ) assume A is linearly-independent ; ::_thesis: ex I being Basis of V st A c= I then consider B being Subset of V such that A1: A c= B and A2: B is base by Th18; reconsider B = B as Basis of V by A2, Def4; take B ; ::_thesis: A c= B thus A c= B by A1; ::_thesis: verum end; theorem :: MOD_3:22 for R being Skew-Field for V being LeftMod of R for A being Subset of V st Lin A = V holds ex I being Basis of V st I c= A proof let R be Skew-Field; ::_thesis: for V being LeftMod of R for A being Subset of V st Lin A = V holds ex I being Basis of V st I c= A let V be LeftMod of R; ::_thesis: for A being Subset of V st Lin A = V holds ex I being Basis of V st I c= A let A be Subset of V; ::_thesis: ( Lin A = V implies ex I being Basis of V st I c= A ) assume Lin A = V ; ::_thesis: ex I being Basis of V st I c= A then consider B being Subset of V such that A1: B c= A and A2: B is base by Th19; reconsider B = B as Basis of V by A2, Def4; take B ; ::_thesis: B c= A thus B c= A by A1; ::_thesis: verum end;