
theorem
  for n being Nat st n > 0 holds [\ log(2, n) /] + 1 = [\ log(2, 2*n + 1 ) /]
proof
  let n be Nat;
  assume
A1: n > 0;
  then [\ log(2, 2*n + 1) /] = [\ log(2, 2*n) /] by Th13
    .= [\ log (2, 2) + log(2, n) /] by A1,POWER:53
    .= [\ log(2, n) + 1 /] by POWER:52
    .= [\ log(2, n) /] + 1 by INT_1:28;
  hence thesis;
end;
