
theorem Th1:
  for a being positive Nat,
      n,m being Nat st n >= m holds a|^n >= a|^m
proof
  let a be positive Nat;
  let n,m be Nat;
  assume n >= m;
  then a|^m divides a|^n by NEWTON:89;
  hence thesis by INT_2:27;
end;
