reserve a,b,i,k,m,n for Nat;
reserve s,z for non zero Nat;
reserve c for Complex;

theorem Th61:
  1 <= a implies 2|^(2|^n) + (6*a-1) > 6
  proof
    assume 1 <= a;
    then 6*1 <= 6*a by XREAL_1:64;
    then
A1: 6*1-1 <= 6*a-1 by XREAL_1:9;
    0+1 <= 2|^n by NAT_1:13;
    then 2 <= 2|^(2|^n) by PREPOWER:12;
    then 2+5 <= 2|^(2|^n) + (6*a-1) by A1,XREAL_1:7;
    hence thesis by XXREAL_0:2;
  end;
