theorem
  for f being Morphism of C opp holds opp(I --> f) = I --> (opp f)
proof
  let f be Morphism of C opp;
  set F = I --> f, F9 = I --> (opp f);
  now
    let x;
    assume
A1: x in I;
    then F/.x = f & F9/.x = opp f by Th2;
    hence opp F/.x = F9/.x by A1,Def4;
  end;
  hence thesis by Th1;
end;
