theorem Th135:
  x <> 0 & x <> 1 & x <> 2 & x <> 3 & x <> 4
proof
  x in VAR;
  then
A1: ex i st x = i & 5 <= i;
  assume x = 0 or x = 1 or x = 2 or x = 3 or x = 4;
  hence contradiction by A1;
end;
