theorem ThMak7:
  for S being (TE) (IE) (SC) (FS') non empty TarskiGeometryStruct holds
    S is (FS)
  proof
    let S be (TE) (IE) (SC) (FS') non empty TarskiGeometryStruct;
    S is (RE) by ThMak6;
    hence thesis;
  end;
