theorem
  H is being_membership iff H/(x,y) is being_membership
proof
  thus H is being_membership implies H/(x,y) is being_membership
  by Th155;
  assume H/(x,y) is being_membership;
  then
A1: H/(x,y).1 = 1 by ZF_LANG:19;
  3 <= len H by ZF_LANG:13;
  then 1 <= len H by XXREAL_0:2;
  then
A2: 1 in dom H by FINSEQ_3:25;
  y <> 1 by Th135;
  then H.1 <> x by A1,A2,Def3;
  then 1 = H.1 by A1,A2,Def3;
  hence thesis by ZF_LANG:25;
end;
