theorem Th16:
  |.Kv.| c= [#]Kv implies BCS(0,Kv) = Kv
 proof
  assume|.Kv.|c=[#]Kv;
  hence BCS(0,Kv)=subdivision(0,center_of_mass V,Kv) by Def6
   .=Kv by SIMPLEX0:61;
 end;
