theorem
  for F being Function of I,the carrier' of C holds F*f = F"*"(I-->f)
proof
  let F be Function of I,the carrier' of C;
  now
    let x;
    assume
A1: x in I;
    hence (F*f)/.x = (F/.x)(*)f by Def5
      .= (F/.x)(*)((I-->f)/.x) by A1,Th2
      .= (F"*"(I-->f))/.x by A1,Def7;
  end;
  hence thesis by Th1;
end;
