theorem
 for n,m being Element of NAT holds
  n <> m implies n-thRWNotIn L <> m-thRWNotIn L
proof let n,m be Element of NAT;
  assume n <> m;
  then n < m or m < n by XXREAL_0:1;
  then
A1: min ((RWNotIn-seq L).n) <> min ((RWNotIn-seq L).m) by Th24;
  assume n-thRWNotIn L = m-thRWNotIn L;
  hence contradiction by A1,AMI_3:10;
end;
