theorem Th29:
  seq is non-decreasing & not seq is bounded_above implies seq is
  divergent_to+infty
proof
  assume that
A1: seq is non-decreasing and
A2: not seq is bounded_above;
  let r;
  consider n such that
A3: r+1<=seq.n by A2;
  take n;
  let m;
  assume n<=m;
  then seq.n<=seq.m by A1,SEQM_3:6;
  then r+1<=seq.m by A3,XXREAL_0:2;
  hence thesis by Lm1;
end;
