theorem Th35:
  { x1,x1,x2,x3,x4,x5,x6,x7 } = { x1,x2,x3,x4,x5,x6,x7 }
proof
  thus { x1,x1,x2,x3,x4,x5,x6,x7 } = { x1,x1 } \/ { x2,x3,x4,x5,x6,x7 } by Th23
    .= { x1 } \/ { x2,x3,x4,x5,x6,x7 } by Th29
    .= { x1,x2,x3,x4,x5,x6,x7 } by Th16;
end;
