theorem Th3: m-tuples_on (A/\B)=m-tuples_on A /\ (m-tuples_on B)
proof
m-tuples_on (A/\B) = m-tuples_on A /\ (B*) by Th2 .=
m-tuples_on A /\ (m-tuples_on B) by Th1; hence thesis;
end;
