theorem Th36:
  uncurry {} = {} & uncurry' {} = {}
proof
A1: now
    set t = the Element of dom uncurry {};
    assume dom uncurry {} <> {};
    then ex x,g,y st t = [x,y] & x in dom {} & g = {} .x & y in dom g by Def2;
    hence contradiction;
  end;
  hence uncurry {} = {};
  thus thesis by A1,Th1,RELAT_1:41;
end;
