theorem Th44:
  for th holds th rExpSeq is summable &
  Sum(th rExpSeq)=Re(Sum(th ExpSeq))
proof
  let th;
   Sum(th ExpSeq) =Sum(Re (th ExpSeq))+(Sum(Im (th ExpSeq)))*<i> & Sum(th
  rExpSeq)=Sum(Re (th ExpSeq)) by Th43,COMSEQ_3:53;
  hence thesis by Th43,COMPLEX1:12;
end;
