theorem
  for a being object holds 3 |-> a = <*a,a,a*>
proof let a be object;
  thus 3 |-> a = (2+1) |-> a .= (2|->a)^<*a*> by Th58
    .= <*a,a*>^<*a*> by Th59
    .= <*a,a,a*>;
end;
