theorem
  for L1,L2 being List of X holds
  ROUGH(<*L1,L2*>,1) = L1 OR L2
  proof
    let L1,L2 be List of X;
    len <*L1,L2*> = 2 & rng <*L1,L2*> = {L1,L2} & union {L1,L2} = L1 OR L2 &
    Union <*L1,L2*> = union rng <*L1,L2*>
    by CARD_3:def 4,FINSEQ_1:44,FINSEQ_2:127,ZFMISC_1:75;
    hence ROUGH(<*L1,L2*>,1) = L1 OR L2 by Th63;
  end;
