theorem
  B c= A* implies A+ ^^ B c= A+ & B ^^ (A+) c= A+
proof
  assume
A1: B c= A*;
  then B ^^ (A+) c= A* ^^ (A+) by FLANG_1:17;
  then
A2: B ^^ (A+) c= A+ ^^ (A*) by Th86;
  A+ ^^ B c= A+ ^^ (A*) by A1,FLANG_1:17;
  hence thesis by A2,Th92;
end;
