theorem Th9:
  b1:=(f1, a1) = b2:=(f2, a2) implies a1 = a2 & b1 = b2 & f1 = f2
proof
A1: <*b1,f1,a1*>.1 = b1 & <*b1,f1,a1*>.2 = f1;
A2: <*b1,f1,a1*>.3 = a1 & <*b2,f2,a2*>.1 = b2;
A3: <*b2,f2,a2*>.2 = f2 & <*b2,f2,a2*>.3 = a2;
  assume b1:=(f1, a1) = b2:=(f2, a2);
  hence thesis by A1,A2,A3,XTUPLE_0:3;
end;
