:: SERIES_2 semantic presentation
theorem Th1: :: SERIES_2:1
Lemma2:
for b1 being real number holds b1 |^ 3 = (b1 * b1) * b1
Lemma3:
for b1 being real number holds b1 |^ 3 = (b1 |^ 2) * b1
Lemma4:
for b1, b2 being real number holds
( 4 = 2 |^ 2 & (b1 + b2) |^ 2 = ((b1 |^ 2) + ((2 * b1) * b2)) + (b2 |^ 2) )
Lemma5:
for b1 being real number holds (b1 + 1) |^ 3 = (((b1 |^ 3) + (3 * (b1 |^ 2))) + (3 * b1)) + 1
Lemma6:
for b1 being Nat holds ((b1 * ((2 * b1) + 1)) * (((3 * (b1 |^ 2)) + (3 * b1)) - 1)) + (((b1 + 1) |^ 3) * 30) = ((b1 + 2) * ((2 * (b1 + 1)) + 1)) * (((3 * ((b1 + 1) |^ 2)) + (3 * (b1 + 1))) - 1)
Lemma7:
for b1 being real number holds
( (b1 + 1) |^ 4 = ((((b1 |^ 4) + (4 * (b1 |^ 3))) + (6 * (b1 |^ 2))) + (4 * b1)) + 1 & (b1 + 1) |^ 5 = (((((b1 |^ 5) + (5 * (b1 |^ 4))) + (10 * (b1 |^ 3))) + (10 * (b1 |^ 2))) + (5 * b1)) + 1 )
theorem Th2: :: SERIES_2:2
Lemma8:
for b1 being Nat holds
( 1 - (1 / (b1 + 2)) = (b1 + 1) / (b1 + 2) & 1 / ((b1 + 1) ! ) = (b1 + 2) / (((b1 + 1) ! ) * (b1 + 2)) )
Lemma9:
for b1 being Nat holds (1 / (b1 + 1)) - (2 / ((b1 + 1) * (b1 + 3))) = 1 / (b1 + 3)
Lemma10:
for b1 being Nat holds (1 / (b1 + 1)) - (3 / ((b1 + 1) * (b1 + 4))) = 1 / (b1 + 4)
Lemma11:
for b1 being Nat holds ((b1 |^ 2) + (3 * b1)) + 2 = (b1 + 1) * (b1 + 2)
Lemma12:
for b1 being Nat holds (((b1 * (4 * (b1 |^ 2))) + (11 * b1)) + (12 * (b1 |^ 2))) + 3 = (b1 + 1) * ((4 * ((b1 + 1) |^ 2)) - 1)
Lemma13:
for b1 being Nat holds ((b1 + 1) |^ 2) * ((2 * ((b1 + 1) |^ 2)) - 1) = ((((((b1 |^ 2) * (b1 |^ 2)) * 2) + ((12 - 1) * (b1 |^ 2))) + (8 * (b1 |^ 3))) + (6 * b1)) + 1
Lemma14:
for b1 being Nat holds (b1 + 2) * ((((b1 + 1) |^ 2) + (b1 + 1)) - 1) = (((b1 |^ 3) + (5 * (b1 |^ 2))) + (7 * b1)) + 2
Lemma15:
for b1, b2 being real number
for b3 being Real_Sequence st ( for b4 being Nat holds b3 . b4 = (b1 * b4) + b2 ) holds
for b4 being Nat holds (Partial_Sums b3) . b4 = ((((b1 * (b4 + 1)) * b4) / 2) + (b4 * b2)) + b2
theorem Th3: :: SERIES_2:3
theorem Th4: :: SERIES_2:4
theorem Th5: :: SERIES_2:5
theorem Th6: :: SERIES_2:6
theorem Th7: :: SERIES_2:7
theorem Th8: :: SERIES_2:8
theorem Th9: :: SERIES_2:9
theorem Th10: :: SERIES_2:10
theorem Th11: :: SERIES_2:11
theorem Th12: :: SERIES_2:12
theorem Th13: :: SERIES_2:13
theorem Th14: :: SERIES_2:14
theorem Th15: :: SERIES_2:15
theorem Th16: :: SERIES_2:16
theorem Th17: :: SERIES_2:17
theorem Th18: :: SERIES_2:18
Lemma16:
for b1 being Nat holds ((b1 |^ 2) * (((2 * (b1 |^ 2)) + (2 * b1)) - 1)) + (((b1 + 1) |^ 3) * 12) = ((b1 + 2) |^ 2) * (((2 * ((b1 + 1) |^ 2)) + (2 * (b1 + 1))) - 1)
theorem Th19: :: SERIES_2:19
Lemma17:
for b1 being Nat holds ((b1 + 2) * ((2 * (b1 + 1)) + 1)) * ((((3 * ((b1 + 1) |^ 4)) + (6 * ((b1 + 1) |^ 3))) - (3 * (b1 + 1))) + 1) = ((((((6 * (b1 |^ 6)) + (57 * (b1 |^ 5))) + (216 * (b1 |^ 4))) + (414 * (b1 |^ 3))) + (419 * (b1 |^ 2))) + (211 * b1)) + 42
theorem Th20: :: SERIES_2:20
Lemma18:
for b1 being Nat holds ((b1 + 2) |^ 2) * (((((3 * ((b1 + 1) |^ 4)) + (6 * ((b1 + 1) |^ 3))) - ((b1 + 1) |^ 2)) - (4 * (b1 + 1))) + 2) = ((b1 |^ 2) * (((((3 * (b1 |^ 4)) + (6 * (b1 |^ 3))) - (b1 |^ 2)) - (4 * b1)) + 2)) + (((b1 + 1) |^ 5) * 24)
Lemma19:
for b1 being Nat holds (2 |^ (b1 + 2)) + ((- 1) |^ (b1 + 2)) > 0
Lemma20:
for b1 being Nat holds (2 |^ (b1 + 3)) + ((- 1) |^ (b1 + 3)) > 0
theorem Th21: :: SERIES_2:21
theorem Th22: :: SERIES_2:22
theorem Th23: :: SERIES_2:23
theorem Th24: :: SERIES_2:24
theorem Th25: :: SERIES_2:25
theorem Th26: :: SERIES_2:26
theorem Th27: :: SERIES_2:27
theorem Th28: :: SERIES_2:28
theorem Th29: :: SERIES_2:29
theorem Th30: :: SERIES_2:30
theorem Th31: :: SERIES_2:31
theorem Th32: :: SERIES_2:32
theorem Th33: :: SERIES_2:33
theorem Th34: :: SERIES_2:34
theorem Th35: :: SERIES_2:35
theorem Th36: :: SERIES_2:36
theorem Th37: :: SERIES_2:37
theorem Th38: :: SERIES_2:38
theorem Th39: :: SERIES_2:39
theorem Th40: :: SERIES_2:40
theorem Th41: :: SERIES_2:41
theorem Th42: :: SERIES_2:42